Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Five boxes of bananas sell for Rs. 30. how many boxes can you buy for Rs.9? 2385 05b5cc636e4d2b4197774b9ff
5b5cc636e4d2b4197774b9ff- 12false
- 21.5true
- 31.25false
- 42.5false
- उत्तर देखें
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उत्तर : 2. "1.5"
व्याख्या :
Answer: B) 1.5 Explanation: Given Five boxes of bananas sell for Rs. 30. => 1 Box of Bananas for = 30/5 = Rs. 6 Then, for Rs. 9 => 9/6 = 3/2 = 1.5 Hence, for Rs. 9, 1.5 box of bananas can buy.
प्र: 40 % of 250 = 50% ? 2384 05b5cc7c9e4d2b41977750ea4
5b5cc7c9e4d2b41977750ea4- 1200true
- 2100false
- 3150false
- 4400false
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उत्तर : 1. "200"
व्याख्या :
Answer: A) 200 Explanation: As per given 40100×250 =50100×x ⇒x=200
प्र: Find the least number with which 16200 should be multiplied, to make it a perfect cube ? 2367 05b5cc6eee4d2b4197774eec3
5b5cc6eee4d2b4197774eec3- 145true
- 248false
- 3360false
- 436false
- उत्तर देखें
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उत्तर : 1. "45"
व्याख्या :
Answer: A) 45 Explanation: 16200 = 23×34×52 A perfect cube has a property of having the indices of all its prime factors divisible by 3. Required number = 32×5 = 9x5 = 45.
प्र: The minimum number of half years in which a sum of money kept at 60% compound interest will be quadrupled is ? 2363 05b5cc77fe4d2b4197775016f
5b5cc77fe4d2b4197775016f- 12false
- 24false
- 33false
- 46true
- उत्तर देखें
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उत्तर : 4. "6"
व्याख्या :
Answer: D) 6 Explanation: Let us assume Amount be 100 Rs and we calculate in CI First year 60% of 100 = 60 amount (100+60) is 160 Second year 60% of 160 = 96 amount (160+96) is 256 Third year 60% of 256 =153.6 amount (256+153.6) is 409.6 Here the Amount of 100 Rs is quadrapled in 3 years. One year contains 2 half years Three year has 6 half years. Therefore, It takes 6 half years.
प्र: Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ? 2363 05b5cc71be4d2b4197774f50d
5b5cc71be4d2b4197774f50d- 125 yearsfalse
- 224 yearsfalse
- 323 yearstrue
- 422 yearsfalse
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उत्तर : 3. "23 years"
व्याख्या :
Answer: C) 23 years Explanation: Ayush's present age = 10 years.His mother's present age = (10 + 20) years = 30 years.Ayush's father's present age = (30 + 5) years = 35 years.Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years. Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.
प्र: Sushma joins a job at 20 yrs. First 3 years salary is 10,000 p.a. Afterwards every year increment of 2,000 per year for 10 years. Then salary becomes constant till retirement. At retirement average salary is 25,000. (throughout career). At what age Sushma retires ? 2362 05b5cc711e4d2b4197774f3be
5b5cc711e4d2b4197774f3be- 150 yrstrue
- 247 yrsfalse
- 345 yrsfalse
- 442 yrsfalse
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उत्तर : 1. "50 yrs"
व्याख्या :
Answer: A) 50 yrs Explanation: Let age of retirement = Sso according to the given condition 25000(x-20)=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)= 30000 + 210000 + 30000S-990000= 30000S - 750000or 25000S - 500000 = 30000x - 750000or 5000x = 250000or S = 50 yrs.
प्र: Srinivas bought 10 cycles for Rs. 1,750 each. He sold 4 cycles for Rs 8,400, 3 for Rs 1900 each . At what price should he sell the remaining cycles so as to earn an average profit of Rs 320 per cycle ? 2358 05b5cc718e4d2b4197774f4c7
5b5cc718e4d2b4197774f4c7- 1Rs. 1580false
- 2Rs. 2200true
- 3Rs. 1785false
- 4Rs. 1950false
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उत्तर : 2. "Rs. 2200"
व्याख्या :
Answer: B) Rs. 2200 Explanation: He sold 4 cycles for Rs. 8400[It means each cycle price is Rs. 2100]And again he sold 3 cycles for Rs. 1900 eachIf he want to gain avg profit on each cycle is Rs. 320 per cycle.So profit for 10 cycles is @ Rs.320 is,10 x 320 = Rs. 3200He already got Rs. 1850 profit by selling 7 cycles.Now, remaining amount is 3200 - 1850 = 1350So from remaining 3 cycles we want to get Rs. 1350 profit ,1350/3 = 450so he must sell remaining 3 cycles at Rs. 2200 each one.
प्र: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2358 05b5cc745e4d2b4197774fa0e
5b5cc745e4d2b4197774fa0e- 139 daysfalse
- 237 daysfalse
- 335 daystrue
- 433 daysfalse
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उत्तर : 3. "35 days"
व्याख्या :
Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.