Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2   and simple interest for 5 years = Rs. 2400   Now, we know that  C.I = P1+R100n - 1   => 1513.2 = P1+R1003 - 1 ...........(A)   And S.I = PTR/100   => 2400 = P5R/100 ..................(B)   By solving (A) & (B), we get   R = 5%.

Answer: A) 3/91 Explanation: In a circle of n different persons, the total number of arrangements possible = (n - 1)!Total number of arrangements = n(S) = (15 – 1)! = 14 !Taking three persons as a unit, total persons = 13 (in 4 units)Therefore no. of ways for these 13 persons to around the circular table = (13 - 1)! = 12!In any given unit, 3 particular person can sit in 3!. Hence total number of ways that any three person can sit =n(E) = 12! X 3!Therefore P (E) = probability of three persons sitting together = n(E) / n(S) = 12! X 3 ! / 14!= 12!x3x2 / 14x13x12! = 6/14x13 = 3/91

Answer: B) 5 Explanation: Let M, N and O worked together for x days. From the given data,M alone worked for 8 daysM,N,O worked for x daysN, O worked for 1 day But given thatM alone can complete the work in 18 daysN alone can complete the work in 36 daysO alone can complete the work in 54 days The total work can be the LCM of 18, 6, 54 = 108 units M's 1 day work = 108/18 = 6 unitsN's 1 day work = 108/36 = 3 unitsO's 1 day work = 108/54 = 2 units Now, the equation is8 x 6 + 11x + 5 x 1 = 10848 + 11x + 5 = 10811x = 103 - 4811x = 55x = 5 days. Hence, all M,N and O together worked for 5 days.

Answer: D) Rs. 616 Explanation: Let the average expenditure per head be Rs. pNow, the expenditure of the mess for old students is Rs. 44pAfter joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33Therefore, 59(p-3) = 44p + 3359p - 177 = 44p + 3315p = 210 => p = 14Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

Answer: A) 45 Explanation: 16200 = 23×34×52   A perfect cube has a property of having the indices of all its prime factors divisible by 3.   Required number = 32×5 = 9x5 = 45.

Answer: B) 3/4 hrs Explanation: Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time   so 1/3rd of the usual time = 15minor usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.

Answer: C) 23 years Explanation: Ayush's present age = 10 years.His mother's present age = (10 + 20) years = 30 years.Ayush's father's present age = (30 + 5) years = 35 years.Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years. Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.

Answer: A) Rs. 7500 Explanation: Arun : Varun : Akhil = (20000 x 24) : (15000 x 24) : (20000 x 18) = 4:3:3 B's share = 25000 x 3/10 = Rs. 7500.