Answer: B) 2 Explanation: Given a2 + b2 = c2   Now  1logc+ab  + 1logc-ab    = logbc+a + logbc-a   = logbc2-a2 = 2logbb = 2

Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.

Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%

Answer: C) Rs. 1200 Explanation: Let Althaf lent Rs. A at 14% per year.Hence, Money lent at 12% = (1500-A);Given, total interest = Rs. 186.{(A x 14x 1)/100} + {[(1500-A) x 12 x 1/100]} = 186;14A/100 + (18000 -12A)/100 = 186;14A + 18000 - 12A = 186x100;2A = 18600-18000;A = 600/2 = Rs. 300.Hence, money lent at 12% = 1500-300 = Rs. 1200.

Answer: B) 105/103 Explanation: As given equal amounts of alloys are melted, let it be 1 kg. Required ratio of gold and silver = 513 + 58813 + 38 = 105103.   Hence, ratio of gold and silver in the resulting alloy = 105/103.

Answer: A) 60 Explanation: Let, no. of rice bowl = xno. of dal bowl = yno. of meat bowl = z Then, x + y + z = 65 ....(1) Also given that, 2x = 3y = 4z substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),We get x = 30. As 1 rice bowl is shared between 2 guests, Therefore, there are 60 guests.

Answer: A) 5:1 Explanation: Let the speed of the man in still water = p kmph Speed of the current = s kmph Now, according to the questions (p + s) x 10 = (p - s) x 15 2p + 2s = 3p - 3s => p : s = 5 : 1   Hence, ratio of his speed to that of current = 5:1.

Answer: C) 2 Explanation: Let work done by 1 man in i day be m and Let work done by 1 boy in 1 day be b From the given data, 4(5m + 3b) = 23 20m + 12b = 23....(1) 2(3m + 2b) = 7 6m + 4b = 7 ....(2) By solving (1) & (2), we get m = 1, b = 1/4 Let the number of required boys = n 6(7 1 + n x 1/4) = 45 => n = 2.