Answer: B) 50 Explanation: Sony and her brother's age sum is 31Let Sony's mother's age be 'x'.Now the conditions given for both of their ages related to their mom is1/5(x-15) + 3/5(x-10) = 31x-15 + 3x-30 = 1554x-45 = 1554x = 200x = 50So, Mother's age = 50. Cross verification : 15 years ago age = 35 => Sony age = 710 years ago age = 40 => bro age = 24 Sum = 24 + 7 = 31.

Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.

Answer: D) 13.742% gain Explanation: Let CP = 100,42 % increase => SP = 14210 % discount in SP => ((142 x 10)/100) = 14.2So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.0582nd SP = (127.8 - 14.058) = 113.742, So finally CP = 100, SP = 113.742, => gain = 13.742%.

Answer: A) 175 Explanation: Let the number of males be 'M'Let the number of females be 'F'From the given conditions,(F-15)=2M.....(i)F=5(M-45).....(ii)By solving the equations (1) & (2) we get M = 80 Then substitute M = 80 in (1)F = 2M + 15F = 2 x 80 + 15=> F = 175Therefore, number of males = 80 and females = 175 in the party.

Answer: C) 11 Explanation: Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.Given SD makes 1/4 th of the total fleet.=> 8 = 1/4 (21 + x)=> 32 = 21 + x=> x = 11 Therefore, the company has 11 small cars.

Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.

Answer: A) 2893 Explanation: For solving this problem first we would break the whole range in 5 sections 1) From 1 to 9Total number of zero in this range = 0 2) From 10 to 99Total possibilities = 9*1 = 9 ( here 9 is used for the possibilities of a non zero integer) 3) From 100 to 999 - three type of numbers are there in this range a) x00 b) x0x c) xx0 (here x represents a non zero number)Total possibilities for x00 = 9*1*1 = 9, hence total zeros = 9*2 = 18for x0x = 9*1*9 = 81, hence total zeros = 81similarly for xx0 = 81 total zeros in three digit numbers = 18 + 81 +81 = 180 4) From 1000 to 9999 - seven type of numbers are there in this rangea)x000 b)xx00 c)x0x0 d)x00x e)xxx0 f)xx0x g)x0xxTotal possibilities for x000 = 9*1*1*1 = 9, hence total zeros = 9*3 = 27 for xx00 = 9*9*1*1 = 81, hence total zeros = 81*2 = 162 for x0x0 = 9*1*9*1 = 81, hence total zeros = 81*2 = 162for x00x = 9*1*1*9 = 81, hence total zeros = 81*2 = 162 for xxx0 = 9*9*9*1 = 729, hence total zeros = 729*1 = 729for xx0x = 9*9*1*9 = 729, hence total zeros = 729*1 = 729for x0xx = 9*1*9*9 = 729, hence total zeros = 729*1 = 729total zeros in four digit numbers = 27 + 3*162 + 3*729 = 2700thus total zeros will be 0+9+180+2700+4 (last 4 is for 4 zeros of 10000)= 2893

Answer: D) 432 Explanation: There are 600 Kabaddi players4% wear knee band on one legRemaining players = 600 x 0.96 = 576Of the remaining, 25% wear knee bands on both leg and Of the remaining, 75% do not wear knee bands .So players not wearing knee bands = 0.75 x 576 = 576 x 3/4 = 144 x 3 = 432.