Quantitative Aptitude Practice Question and Answer
8Q: When Raj Tarun was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Raj Tarun's brother is 6 years older than Raj Tarun and his mother is 3 years younger than his father, how old was Raj Tarun's sister when Raj Tarun was born ? 2251 05b5cc74ae4d2b4197774fa6d
5b5cc74ae4d2b4197774fa6d- 15false
- 210true
- 315false
- 48false
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Answer : 2. "10"
Explanation :
Answer: B) 10 Explanation: Raj Tarun's age = 0 when he was born.Then, given his brother is 6 years old.Then his father is 6 + 32 = 38 when Raj Tarun was bornAnd his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was bornand his sister is 25 year younger than his mother so Raj Tarun's sister was 10 years old when Raj Tarun was born.
Q: A seller uses 840 gm in place of 1 kg to sell his goods. Find his actual profit/loss % When he sells his article on 4% loss on cost price ? 1526 15b5cc74ae4d2b4197774fa72
5b5cc74ae4d2b4197774fa72- 114.28 % profittrue
- 224.18 % profitfalse
- 314.28 % lossfalse
- 424.18 % lossfalse
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Answer : 1. "14.28 % profit"
Explanation :
Answer: A) 14.28 % profit Explanation: Let 1kg of Rs. 100 then 840gm is of Rs. 84.Now (label on can 1kg but contains 840kg ) so for customer it is of Rs. 100 and further gives 4% discount [he sells his article on 4% loss on cost price.] So now S.P = Rs. 96But actually it contains 840 gm so C.P for shopkeeper = Rs. 84S.P = Rs. 96C.P = Rs. 84Profit% = {(S.P-C.P)/C.P}x100{(96-84)/84} x 100 = 14.28571429% PROFIT.
Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 4954 05b5cc74ae4d2b4197774fa68
5b5cc74ae4d2b4197774fa68- 120 kmfalse
- 216 kmfalse
- 314 kmfalse
- 410 kmtrue
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Answer : 4. "10 km"
Explanation :
Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.
Q: Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ? 4455 05b5cc745e4d2b4197774fa5e
5b5cc745e4d2b4197774fa5e- 1140 kmstrue
- 2120 kmsfalse
- 396 kmsfalse
- 4142 kmsfalse
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Answer : 1. "140 kms"
Explanation :
Answer: A) 140 kms Explanation: It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, theDistance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 kmSo train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutesSo distance from A = Distance traveled by 2nd train in 3 hr. 30 min = 40 x 3.5 = 140 km.
Q: Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ? 1570 05b5cc745e4d2b4197774fa54
5b5cc745e4d2b4197774fa54- 164false
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Answer : 3. "71"
Explanation :
Answer: C) 71 Explanation: To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51). Therefore, HCF of 923, 1207 and 1349 is 71.
Q: You drive to the store at 20 kmph and return by the same route at 30 kmph. Discounting the time spent at the store, what was your average speed ? 1057 05b5cc745e4d2b4197774fa4a
5b5cc745e4d2b4197774fa4a- 125 kmphfalse
- 224 kmphtrue
- 326 kmphfalse
- 422 kmphfalse
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Answer : 2. "24 kmph"
Explanation :
Answer: B) 24 kmph Explanation: Average speed=total distance/total timeLet distance to store be Kthen, total time =(K/20)+(K/30)=K/12and, total time =(2K)so average speed= 2K / (K/12) = 24kmph.
Q: A Product is supported each week by the same three Product supporters. Last month the first supporter took 440 calls, the second took 360 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three supporters each increase their work proportionately, how many more calls will the second supporter take this month than last month ? 1398 05b5cc745e4d2b4197774fa40
5b5cc745e4d2b4197774fa40- 1131 callstrue
- 2160 callsfalse
- 3491 callsfalse
- 4600 callsfalse
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Answer : 1. "131 calls"
Explanation :
Answer: A) 131 calls Explanation: 1st supporter recieve 440 calls 2nd supporter recieve 360 calls 3rd supporter recieve 300 calls So total calls = 1100 calls ; Calls this month= 1500 So remaining calls to be distributed is 400 So Now Ratio 1st:2nd:3rd ==> 440:360:300=> 22:18:15 Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400=> (18/55) x 400 => 131 CallsSo 131 more Calls than last month.
Q: If a number 72k23l is divisible by 88. Then find value of k and l ? 2173 05b5cc745e4d2b4197774fa36
5b5cc745e4d2b4197774fa36- 1k=8 & l=2false
- 2k=7 & l=2true
- 3k=8 & l=3false
- 4k=7 & l=1false
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Answer : 2. "k=7 & l=2"
Explanation :
Answer: B) k=7 & l=2 Explanation: If a number to be divisile by 88, it should be divisible by both "8" and "11" Check for '8' :For a number to be divisible by "8", the last 3-digit should be divisible by "8"Here 72x23y --> last 3-digit is '23y'So y=2 [ (i.e) 232 is absolutely divisible by "8"] Chech for '11' :For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"(7 + x + 3) - (2 + 2 + y)(7 + x + 3) - (2 + 2 + 2)(10 + x) - 6 should be divisible by "11"for x = 7=> 17 - 6 = 11 [ which is absolutely divisible by "11"] So x = 7 , y= 2.