Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें
8प्र: Suppose today is Friday, what day of the week will it be 65 days from now? 2878 05b5cc69be4d2b4197774c7de
5b5cc69be4d2b4197774c7de- 1Saturdayfalse
- 2Sundaytrue
- 3Fridayfalse
- 4Thursdayfalse
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उत्तर : 2. "Sunday"
व्याख्या :
Answer: B) Sunday Explanation: The day of the week repeats every 7 days. Given today is Friday. Again Friday is repeated on the 7th day, 14th,... on 7 multiple days. Hence, Friday is on the 63rd day, as 63 is multiple of 7. Now, the required day of the week on the 65th day is Sunday.
प्र: The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ? 2877 05b5cc709e4d2b4197774f267
5b5cc709e4d2b4197774f267- 163 and 49true
- 264 and 48false
- 362 and 46false
- 464 and 49false
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उत्तर : 1. "63 and 49"
व्याख्या :
Answer: A) 63 and 49 Explanation: Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14=> x - y = 2 product of numbers = product of their hcf and lcm=> 7x * 7y = 441 * 7=> x * y = 63 Now, we havex * y = 63 , x - y = 2=> x = 9 , y = 7 The numbers are 7x and 7y=> 63 and 49
प्र: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 2866 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
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उत्तर : 2. "4 days"
व्याख्या :
Answer: B) 4 days Explanation: Given 10 men take 15 days to complete a work => Total mandays = 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays in 150/37 =~ 4 days
प्र: The ratio of Karthik’s and Kalyan’s ages is 4: 5. If the difference between the present age of Kalyan and the age of Karthik 5 years hence is 3 years, then what is the total of present ages of Karthik and Kalyan? 2865 05b5cc77fe4d2b419777501a1
5b5cc77fe4d2b419777501a1- 156 yearsfalse
- 262 yearsfalse
- 369 yearsfalse
- 472 yearstrue
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उत्तर : 4. "72 years"
व्याख्या :
Answer: D) 72 years Explanation: Let us consider Karthik as K1 and Kalyan as K2. Given k18+k1 and K2 - (K1 + 5) = 3 K2 - K1 = 8 K2 = 8 + K1 Now, k18+k1= 45 => K1 = 32 years Therefore K2 = 40 years. K1 + K2 = 72 years.
प्र: यदि किसी वस्तु को 5 प्रतिशत हानि की बजाय 5 प्रतिशत लाभ पर बेचा जाता, तो विक्रेता को 33.60 रूपये अधिक मिलते। वस्तु का क्रय मूल्य होगा? 2862 05d132a48925caa2d5bbbff5b
5d132a48925caa2d5bbbff5b- 1336true
- 2454false
- 3672false
- 4785false
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उत्तर : 1. "336"
प्र: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 2837 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
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उत्तर : 1. "74"
व्याख्या :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
प्र: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 2832 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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उत्तर : 3. "289"
व्याख्या :
Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 Hence, the odd number in the given number series is 289.
प्र: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 2828 05b5cc6d9e4d2b4197774e807
5b5cc6d9e4d2b4197774e807- 1101 menfalse
- 2112 menfalse
- 3102 mentrue
- 4120 menfalse
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उत्तर : 3. "102 men"
व्याख्या :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.