Quantitative Aptitude Practice Question and Answer
8Q: 96% of the population of a village is 23040. The total population of the village is ? 2732 05b5cc6e7e4d2b4197774ed92
5b5cc6e7e4d2b4197774ed92- 124000true
- 232256false
- 325478false
- 426587false
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Answer : 1. "24000"
Explanation :
Answer: A) 24000 Explanation: Let the total population be 'P' P x (96/100) = 23040 P = 240 * 100 P = 24000.
Q: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 2721 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
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Answer : 1. "74"
Explanation :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
Q: рдирд┐рдореНрдирд▓рд┐рдЦрд┐рдд рдкреНрд░рд╢реНрди рдореЗрдВ рдкреНрд░рд╢реНрди рдЪрд┐рд╣реНрди (?) рдХреЗ рд╕реНрдерд╛рди рдкрд░ рдХреНрдпрд╛ рдЕрдиреБрдорд╛рдирд┐рдд рдорд╛рди рдЖрдирд╛ рдЪрд╛рд╣рд┐рдП?
2718 05d4ab44e108bca202e8a68d0
5d4ab44e108bca202e8a68d0- 18false
- 238false
- 358false
- 468false
- 518true
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Answer : 5. "18"
Q: рдПрдХ рдмрд╕ рдмрд┐рдирд╛ рдХреЛрдИ рд░реВрдХрд╛рд╡рдЯ рдХреЗ 60 рдХрд┐рдореА/рдШрдВрдЯреЗ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдЪрд▓ рд░рд╣реА рд╣реИред рдкрд░рдиреНрддреБ ,рд░реВрдХрд╛рд╡рдЯ рдХреЗ рд╕рд╛рде 50 рдХрд┐рдореА/рдШрдВрдЯрд╛ рдХреА рд░рдлреНрддрд╛рд░ рд╕реЗ рдЪрд▓ рдкрд╛рддреА рд╣реИред рд░реВрдХрд╛рд╡рдЯ рдХреА рджрд░ рдЬреНрдЮрд╛рдд рдХрд░реЗрдВ? 2717 05d15f74644a3a75f13296b7d
5d15f74644a3a75f13296b7d- 115 рдорд┐рдирдЯ рдкреНрд░рддрд┐ рдШрдВрдЯрд╛false
- 220 рдорд┐рдирдЯ рдкреНрд░рддрд┐ рдШрдВрдЯрд╛false
- 312 рдорд┐рдирдЯ рдкреНрд░рддрд┐ рдШрдВрдЯрд╛false
- 410 рдорд┐рдирдЯ рдкреНрд░рддрд┐ рдШрдВрдЯрд╛true
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Answer : 4. "10 рдорд┐рдирдЯ рдкреНрд░рддрд┐ рдШрдВрдЯрд╛"
Q: Find the next number in the series ┬а 143 143 136 110 ? 2715 05b5cc6b6e4d2b4197774d5a8
5b5cc6b6e4d2b4197774d5a8- 191false
- 235false
- 347true
- 469false
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Answer : 3. "47"
Explanation :
Answer: C) 47 Explanation: The next number in the series is 143 143 136 110 ┬а ┬а ┬а 0┬а ┬а 7┬а ┬а ┬а 26 (Differences) ┬а13┬а-┬а1┬а,┬а23┬а-┬а1,┬а33┬а-┬а1,┬а43┬а-┬а1,...Now┬аthe┬аnext┬аnumber┬аis┬аgiven┬аby110┬а-┬а(43┬а-┬а1)┬а=┬а110┬а-┬а63┬а=┬а47.
Q: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ┬а? 2714 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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Answer : 3. "4312 sq.m"
Explanation :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.┬а┬а ┬а2╧Аs = 264 and┬а2╧Аl = 352┬а┬а ┬а ┬аs =┬а2642╧А and l =┬а3522╧А┬а┬а┬а Difference between the areas =╧Аl2-╧Аs2┬а┬а┬а ┬а┬а=┬а╧А1762╧А2-1322╧А2┬а ┬а┬а= 1762╧А-1322╧А┬а┬а ┬а = (176 - 132)(176 + 132) /┬а╧А┬а┬а ┬а = (44 x 308) / (22/7) = 4312 sq.m
Q: Suppose today is Friday, what day of the week will it be 65 days from now? 2702 05b5cc69be4d2b4197774c7de
5b5cc69be4d2b4197774c7de- 1Saturdayfalse
- 2Sundaytrue
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 2. "Sunday"
Explanation :
Answer: B) Sunday Explanation: The day of the week repeats every 7 days. Given today is Friday. Again Friday┬аis repeated on the 7th day, 14th,...┬аon 7 multiple days. Hence, Friday is on the 63rd day, as 63 is multiple of 7. ┬а Now, the required day of the week on the 65th day is Sunday.
Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 2701 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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Answer : 3. "289"
Explanation :
Answer: C) 289 Explanation: Here the given number series is┬а270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 ┬а Hence, the odd number in the given number series is 289.