Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ
рдкреНрд░: Twenty men can do a work in eighteen days. Eighteen women can complete the same work in fifteen days. What is the ratio between the capacity of a woman and a man ? 1795 05b5cc774e4d2b4197775002a
5b5cc774e4d2b4197775002a- 14:5false
- 23:4false
- 34:3true
- 42:3false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 3. "4:3"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 4:3 Explanation: (20 x 18) men can complete the work in in one day. one man's one day work = 1/360 (18 x 15) women can complete the work in 1 day 1 woman's one day work = 1/270 So, required ratio = 1270:1360= 4:3
рдкреНрд░: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2270 05b5cc774e4d2b41977750025
5b5cc774e4d2b41977750025- 110 daystrue
- 215 daysfalse
- 320 daysfalse
- 45 daysfalse
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 1. "10 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
рдкреНрд░: A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ? 2041 05b5cc774e4d2b4197775001b
5b5cc774e4d2b4197775001b- 111/91false
- 24/11false
- 31/11false
- 490/91true
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 4. "90/91"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: D) Option D Explanation: Let S be the sample space. Then,n(s) = number of ways of drawing 4 pearls out of 14 = C414 ways = 14├Ч13├Ч12├Ч114├Ч3├Ч2├Ч1= 1001 Let E be the event of drawing 4 pearls of the same colour.Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5) тЗТC15+ C44+ C15 = 5+1+5 =11 P(E) = n(E)n(S)=111001=191 Required probability = 1-191=9091
рдкреНрд░: In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ? 1338 05b5cc774e4d2b41977750016
5b5cc774e4d2b41977750016- 113true
- 2821false
- 3621false
- 42021false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 1. "13"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) Option A Explanation: Total number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor green. = event taht the flower drawn is blue. --> n(E)= 7 --> P(E)= 721=13
рдкреНрд░: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1691 05b5cc774e4d2b41977750011
5b5cc774e4d2b41977750011- 1205false
- 2194false
- 3209true
- 4159false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 3. "209"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16├Ч C34) + C26├ЧC24 + (C36├Ч C14) + (C46) = (24+90+80+15) = 209.
рдкреНрд░: How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ? 1364 05b5cc774e4d2b4197775000c
5b5cc774e4d2b4197775000c- 115false
- 220true
- 35false
- 410false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 2. "20"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 20 Explanation: Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5. So, there is one way of doing it. Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place. The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it. Required number of numbers = (1 x 5 x 4) = 20.
рдкреНрд░: Out of seven consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed ? 1337 05b5cc774e4d2b41977750007
5b5cc774e4d2b41977750007- 125200true
- 225000false
- 325225false
- 424752false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 1. "25200"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: A) 25200 Explanation: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) =( C37├ЧC24 ) = 210. Number of groups, each having 3 consonants and 2 vowels =210 Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 120. Required number of words = (210 x 120) = 25200.
рдкреНрд░: Find the next number in the series 2, 3, 4, 8, 9, 10, 11, 16, 17, 18, 19, 20,... 1416 05b5cc771e4d2b4197774ffd0
5b5cc771e4d2b4197774ffd0- 127false
- 226true
- 324false
- 425false
- рдЙрддреНрддрд░ рджреЗрдЦреЗрдВ
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рдЙрддреНрддрд░ : 2. "26"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :
Answer: B) 26 Explanation: The pattern is three consecutive numbers and then three consecutive numbers missing.Then four consecutive numbers and then four consecutive numbers missing.Then five consecutive numbers and then five consecutive numbers missing. The next number=20+6=26