Quantitative Aptitude Practice Question and Answer
8Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3717 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
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Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: एच.आर डिपारटमेंट और अकाउंट डिपारटमेंट के पुरूषों का क्रमशः अनुपात है।
3708 25d4ab905108bca202e8a6cd4
5d4ab905108bca202e8a6cd4- 13:17false
- 24:15false
- 32:15true
- 42:13false
- 5इनमें से कोई नहींfalse
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Answer : 3. "2:15"
Q: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current ? 3668 05b5cc6e2e4d2b4197774ec52
5b5cc6e2e4d2b4197774ec52- 11 kmphfalse
- 23.2 kmphfalse
- 31.5 kmphtrue
- 42 kmphfalse
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Answer : 3. "1.5 kmph"
Explanation :
Answer: C) 1.5 kmph Explanation: 72 --- 9 ? ---- 1 => Down Stream = 8 45 ---- 9 ? ---- 1 => Up Stream = 5 Speed od current S = ? S = (8 - 5)/2 = 1.5 kmph.
Q: Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ? 3662 05b5cc6e0e4d2b4197774eb57
5b5cc6e0e4d2b4197774eb57- 13 : 4false
- 24 : 3true
- 32 : 3false
- 43 : 2false
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Answer : 2. "4 : 3"
Explanation :
Answer: B) 4 : 3 Explanation: Let us name the trains as A and B. Then, (A's speed) : (B's speed) = √b : √a = √16 : √9 = 4:3
Q: John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ? 3659 05b5cc75ce4d2b4197774fc84
5b5cc75ce4d2b4197774fc84- 1Rs.16,500false
- 2Rs.17,500true
- 3Rs.14,200false
- 4Rs.15,520false
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Answer : 2. "Rs.17,500"
Explanation :
Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% => Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.
Q: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 kmph. Then find the speed of faster train ? 3657 05b5cc6dee4d2b4197774ea56
5b5cc6dee4d2b4197774ea56- 168 kmphtrue
- 252 kmphfalse
- 376 kmphfalse
- 450 kmphfalse
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Answer : 1. "68 kmph"
Explanation :
Answer: A) 68 kmph Explanation: Let the speed of the faster train be 'X' kmph, Then their relative speed= X - 48 kmphTo cross slower train by faster train, Distance need to be cover = (400 + 600)m = 1 km. and Time required = 180 sec = 180/3600 hr = 1/20 hr.Time = Distance/Speed => 1/20 = 1/(x-48)X = 68 kmph
Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 3652 05b5cc75ee4d2b4197774fcca
5b5cc75ee4d2b4197774fcca- 170 yearsfalse
- 230 yearstrue
- 360 yearsfalse
- 440 yearsfalse
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Answer : 2. "30 years"
Explanation :
Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3651 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, At particular time for all object , ratio of height and shadow are same. Let the height of the pole be 'H' Then 188=H48 => H = 108 m.