IIT JEE Practice Question and Answer
8Q: What is 90 days from today? Hints : Today is 20th January 2017, Sunday 2628 05b5cc6b5e4d2b4197774d516
5b5cc6b5e4d2b4197774d516- 118th April, Fridayfalse
- 220th April, Saturdaytrue
- 321th April, Sundayfalse
- 419th April, Saturdayfalse
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Answer : 2. "20th April, Saturday"
Explanation :
Answer: B) 20th April, Saturday Explanation: Given Today is 20th January 2017, Sunday In january, we have 31 days February - 28 days (Non leap year) March - 31 days April - 30 days => Remaining days => 31 - 20 = 11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days More 20 days to complete 90 days => upto 20th April Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017. Now, the day of the week will be 90/7 => Remainder '6' As the day starts with '0' on sunday 6 => Saturday. Required day is 20th April, Saturday.
Q: If (1 × 2 × 3 × 4 ........ × n) = n!, then 15! - 14! - 13! is equal to ___? 2628 05b5cc6bee4d2b4197774d997
5b5cc6bee4d2b4197774d997- 114 × 13 × 13!false
- 215 × 14 × 14!false
- 314 × 12 × 12!false
- 415 × 13 × 13!true
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Answer : 4. "15 × 13 × 13!"
Explanation :
Answer: D) 15 × 13 × 13! Explanation: 15! - 14! - 13! = (15 × 14 × 13!) - (14 × 13!) - (13!) = 13! (15 × 14 - 14 - 1) = 13! (15 × 14 - 15) = 13! x 15 (14 - 1) = 15 × 13 × 13!
Q: Find the odd man out in the following number series? 5, 4, 9, 32, 273 2621 05b5cc695e4d2b4197774c500
5b5cc695e4d2b4197774c500- 14false
- 29false
- 332true
- 4273false
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Answer : 3. "32"
Explanation :
Answer: C) 32 Explanation: The given number series follows 5, 4, 9, 32, 308 pattern that 5 5 x 1 - 1 = 4 4 x 3 - 3 = 9 9 x 5 - 5 = 40 (not equals to 32) 40 x 7 - 7 = 273 Hence, the odd man in the given number series is 32.
Q: What grows when it eats but dies when it drinks? 2616 05b5cc64de4d2b4197774bcac
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Answer :
Explanation :
A fire grows when it eats but dies when it drinks.
Q: The number of permutations of the letters of the word 'MESMERISE' is ? 2614 05b5cc6ebe4d2b4197774ee5f
5b5cc6ebe4d2b4197774ee5f- 19!/(2!)^{2}x3!true
- 29! x 2! x 3!false
- 30false
- 4Nonefalse
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Answer : 1. "9!/(2!)^{2}x3!"
Explanation :
Answer: A) 9!/(2!)^{2}x3! Explanation: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.Number of arrangements = 9!(2!)2×3!
Q: There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ? 2611 05b5cc73de4d2b4197774f95d
5b5cc73de4d2b4197774f95d- 142 & 24false
- 238 & 26false
- 336 & 24false
- 444 & 28true
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Answer : 4. "44 & 28"
Explanation :
Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers
Q: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 2610 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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Answer : 2. "13 years"
Explanation :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Q: Which of the following metals forms an amalgam with other metals ? 2610 15b5cc6d9e4d2b4197774e86c
5b5cc6d9e4d2b4197774e86c- 1Mercurytrue
- 2Zincfalse
- 3Tinfalse
- 4Leadfalse
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Answer : 1. "Mercury"
Explanation :
Answer: A) Mercury Explanation: