IIT JEE Practice Question and Answer
8Q: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest ? 2773 05b5cc6ebe4d2b4197774eeb9
5b5cc6ebe4d2b4197774eeb9- 120% p.atrue
- 215% p.afalse
- 318% p.afalse
- 424% p.afalse
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Answer : 1. "20% p.a"
Explanation :
Answer: A) 20% p.a Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year. Rate of interest = (100 x 240) / (1200) = 20% p.a
Q: दो धनात्मक संख्याओं का अनुपात 3 : 5 है और संख्या का औसत 48 है। संख्याओं का गुणनफल क्या है? 2768 15b5cc607e4d2b4197774b558
5b5cc607e4d2b4197774b558- 13365false
- 22160true
- 31854false
- 41632false
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Answer : 2. "2160"
Explanation :
Answer: B) 2160 स्पष्टीकरण: माना संख्या 3p और 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12 संख्याएँ 36 और 60 हैं। इसलिए, संख्याओं का गुणनफल = 36 x 60 = 2160।
Q: Which statement about greek sculpture is false? 2764 05b5cc639e4d2b4197774ba6c
5b5cc639e4d2b4197774ba6c- 1The Greeks admired the strength and precision of athletes and wanted to portray athletic figures.false
- 2The three main principles of Greek aesthetics are proportion, movement, and rhythm.false
- 3Greeks sculptures are typically stiffly posed, highly styled figures.true
- 4All the abovefalse
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Answer : 3. "Greeks sculptures are typically stiffly posed, highly styled figures."
Explanation :
Answer: C) Greeks sculptures are typically stiffly posed, highly styled figures. Explanation: Greek Sculpture are typically stiff, posed & highly styled figures is the false answer.
Q: Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ? 2764 05b5cc741e4d2b4197774f9cc
5b5cc741e4d2b4197774f9cc- 1Rs. 1595.14true
- 2Rs. 1793.4false
- 3Rs. 595.14false
- 4Rs. 1551.5false
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Answer : 1. "Rs. 1595.14"
Explanation :
Answer: A) Rs. 1595.14 Explanation: Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3No of ladies, gents and girls are 5, 3, 3Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9so part of gents = (12/56) x 7444 = Rs. 1595.142so part of 1 gents = 1595.142/3 = Rs. 531.71.
Q: Excretion is best described as the removal of 2759 05b5cc699e4d2b4197774c6a0
5b5cc699e4d2b4197774c6a0- 1Undigested material from the digestive tractfalse
- 2Metabolic wastes from a celltrue
- 3Toxic wastes by the process of cyclosisfalse
- 4Water molecules from dipeptide hydrolysisfalse
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Answer : 2. "Metabolic wastes from a cell"
Explanation :
Answer: B) Metabolic wastes from a cell Explanation: Excretion is best described as the removal of Metabolic wastes from a cell.
Q: _ tu _ rt _ s _ _ usrtu _ 2759 05b5cc6d9e4d2b4197774e843
5b5cc6d9e4d2b4197774e843- 1rsutrrfalse
- 2rsurtrfalse
- 3rsurtstrue
- 4rtusrufalse
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Answer : 3. "rsurts"
Explanation :
Answer: C) rsurts Explanation: The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
Q: P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ? 2751 05b5cc6c0e4d2b4197774db05
5b5cc6c0e4d2b4197774db05- 156 daysfalse
- 254 daysfalse
- 360 daysfalse
- 464 daystrue
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Answer : 4. "64 days"
Explanation :
Answer: D) 64 days Explanation: (P+Q)'s 1 day work = 1/24 P's 1 day work = 1/32 => Q's 1 day work = 1/24 - 1/32 = 1/96 Work done by (P+Q) in 8 days = 8/24 = 1/3 Remainining work = 1 - 1/3 = 2/3 Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Q: A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ? 2750 05b5cc71ee4d2b4197774f57c
5b5cc71ee4d2b4197774f57c- 14/3 hrsfalse
- 22/3 hrstrue
- 33/2 hrsfalse
- 41/4 hrsfalse
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Answer : 2. "2/3 hrs"
Explanation :
Answer: B) 2/3 hrs Explanation: Let the original speed and time is S and Tthen distance = S x TNow the speed changes to 2/3S and T is T+20As the distance is sameS x T = 2/3Sx(T+20)solving this we get t = 40 minutes =40/60 = 2/3 hour