IIT JEE Practice Question and Answer
8Q: Thread is to String as Cask is to 3897 05b5cc6b6e4d2b4197774d58e
5b5cc6b6e4d2b4197774d58e- 1Barreltrue
- 2Discfalse
- 3Walletfalse
- 4Boxfalse
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Answer : 1. "Barrel"
Explanation :
Answer: A) Barrel Explanation: Here Thread and String are Synonyms of each other. Then the answer will be the synonym of Cask. Cask is nothing but a large barrel-like container used for storing liquids, typically alcoholic drinks. Ex : Drum, Vessel, Tank, Barrel, Hogshead, Firkin,... Here from the options Barrel is the only synonym of Cask. Thus, Thread : String :: Cask : Barrel
Q: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3895 05b5cc75ee4d2b4197774fcb1
5b5cc75ee4d2b4197774fcb1- 16:31false
- 211:30false
- 37:30true
- 431:6false
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Answer : 3. "7:30"
Explanation :
Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30 Therefore, the ratio is 7 : 30
Q: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 3894 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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Answer : 2. "A loss of Rs. 37"
Explanation :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37
Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 3893 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
- 292false
- 396false
- 4102false
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Answer : 1. "88"
Explanation :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
Q: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ? 3876 05b5cc6e1e4d2b4197774ebbb
5b5cc6e1e4d2b4197774ebbb- 118 daysfalse
- 220 daystrue
- 316 daysfalse
- 414 daysfalse
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Answer : 2. "20 days"
Explanation :
Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8 => 50m + 90w = 48w + 96 w => 1m = 3w 5m + 9w = 5m + 3m = 8m 8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.
Q: Which best describes how air moves during convection? 3873 05b5cc6a0e4d2b4197774ca56
5b5cc6a0e4d2b4197774ca56- 1cool air falls downtrue
- 2warm air falls downfalse
- 3cool air is replaced by warm airfalse
- 4air always falls downfalse
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Answer : 1. "cool air falls down"
Explanation :
Answer: A) cool air falls down Explanation: During convection, cool and dense air falls through the warmer and less dense air. The warm air having less mass is being displaced by the cooler which is much heavy. Convection always involves the air rising through the atmosphere.
Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 3871 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.
Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 3856 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
- 21420false
- 31345false
- 41250true
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Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.