IIT JEE प्रश्न और उत्तर का अभ्यास करें

प्र: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3927 0

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    6:31
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    11:30
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  • 3
    7:30
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  • 4
    31:6
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उत्तर : 3. "7:30"
व्याख्या :

Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30   Therefore, the ratio is 7 : 30

प्र: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work  ? 3926 0

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    18 days
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    20 days
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    16 days
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  • 4
    14 days
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उत्तर : 2. "20 days"
व्याख्या :

Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8  => 50m + 90w = 48w + 96 w    => 1m = 3w 5m + 9w = 5m + 3m = 8m   8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.

प्र: Which supercomputer is developed by the Indian Scientists? 3925 0

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    Super 3
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    Param 808
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    Super 149
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  • 4
    Param 8000
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उत्तर : 4. "Param 8000"
व्याख्या :

Answer: D) Param 8000 Explanation: PARAM 8000 was was the first supercomputer developed by Indian scientists launched on July 01, 1991 is considered India's first supercomputer.   It was indigenously built in 1991 by Centre for Development of Advanced Computing and was replicated and installed at ICAD Moscow in 1991 under Russian collaboration.

प्र: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3921 0

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    10
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    18
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    12
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    15
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उत्तर : 1. "10"
व्याख्या :

Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.

प्र: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 3917 0

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    88
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    92
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    96
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    102
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उत्तर : 1. "88"
व्याख्या :

Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676   Hence the missing number in the given number series is 88.

प्र: Thread is to String as Cask is to 3917 0

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    Barrel
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    Disc
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    Wallet
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    Box
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उत्तर : 1. "Barrel"
व्याख्या :

Answer: A) Barrel Explanation: Here Thread and String are Synonyms of each other. Then the answer will be the synonym of Cask.  Cask is nothing but a large barrel-like container used for storing liquids, typically alcoholic drinks.  Ex : Drum, Vessel, Tank, Barrel, Hogshead, Firkin,...   Here from the options Barrel is the only synonym of Cask.   Thus,  Thread : String :: Cask : Barrel

प्र: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 3911 0

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    20
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    35
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    54
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    40
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उत्तर : 1. "20"
व्याख्या :

Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.

प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 3908 0

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    A gain of Rs. 27
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    A loss of Rs. 37
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    A loss of Rs. 27
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    A gain of Rs. 37
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :

Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is:  64 − 27 = 37 A loss of Rs.37

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