IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3927 05b5cc75ee4d2b4197774fcb1
5b5cc75ee4d2b4197774fcb1- 16:31false
- 211:30false
- 37:30true
- 431:6false
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उत्तर : 3. "7:30"
व्याख्या :
Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30 Therefore, the ratio is 7 : 30
प्र: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ? 3926 05b5cc6e1e4d2b4197774ebbb
5b5cc6e1e4d2b4197774ebbb- 118 daysfalse
- 220 daystrue
- 316 daysfalse
- 414 daysfalse
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उत्तर : 2. "20 days"
व्याख्या :
Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8 => 50m + 90w = 48w + 96 w => 1m = 3w 5m + 9w = 5m + 3m = 8m 8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.
प्र: Which supercomputer is developed by the Indian Scientists? 3925 05b5cc6b8e4d2b4197774d64f
5b5cc6b8e4d2b4197774d64f- 1Super 3false
- 2Param 808false
- 3Super 149false
- 4Param 8000true
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उत्तर : 4. "Param 8000"
व्याख्या :
Answer: D) Param 8000 Explanation: PARAM 8000 was was the first supercomputer developed by Indian scientists launched on July 01, 1991 is considered India's first supercomputer. It was indigenously built in 1991 by Centre for Development of Advanced Computing and was replicated and installed at ICAD Moscow in 1991 under Russian collaboration.
प्र: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3921 05b5cc73de4d2b4197774f91b
5b5cc73de4d2b4197774f91b- 110true
- 218false
- 312false
- 415false
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उत्तर : 1. "10"
व्याख्या :
Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.
प्र: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 3917 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
- 292false
- 396false
- 4102false
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उत्तर : 1. "88"
व्याख्या :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
प्र: Thread is to String as Cask is to 3917 05b5cc6b6e4d2b4197774d58e
5b5cc6b6e4d2b4197774d58e- 1Barreltrue
- 2Discfalse
- 3Walletfalse
- 4Boxfalse
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उत्तर : 1. "Barrel"
व्याख्या :
Answer: A) Barrel Explanation: Here Thread and String are Synonyms of each other. Then the answer will be the synonym of Cask. Cask is nothing but a large barrel-like container used for storing liquids, typically alcoholic drinks. Ex : Drum, Vessel, Tank, Barrel, Hogshead, Firkin,... Here from the options Barrel is the only synonym of Cask. Thus, Thread : String :: Cask : Barrel
प्र: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 3911 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
- 235false
- 354false
- 440false
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उत्तर : 1. "20"
व्याख्या :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.
प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 3908 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37