IIT JEE प्रश्न और उत्तर का अभ्यास करें
8प्र: If 9 = 63 8 = 48 7 = 35 Then 4 = ? 4571 05b5cc696e4d2b4197774c56a
5b5cc696e4d2b4197774c56a- 14false
- 28true
- 312false
- 416false
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उत्तर : 2. "8"
व्याख्या :
Answer: B) 8 Explanation: Here given that 9 = 63, 8 = 48, 7=35, ... The given question follows a pattern that 9 x (9 - 2) = 9 x 7 = 63 8 x (8 - 2) = 8 x 6 = 48 7 x (7 - 2) = 7 x 5 = 35 Similarly, 4 x (4 - 2) = 4 x 2 = 8.
प्र: 19 persons do 19 programs in 19 hours . If they take 15 mins interval and then how much time they need to do 52 programs. 4569 05b5cc754e4d2b4197774fb6d
5b5cc754e4d2b4197774fb6d- 123 hoursfalse
- 247 hrs 15 minfalse
- 352 hrs 15 mintrue
- 422 hrs 15 minfalse
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उत्तर : 3. "52 hrs 15 min"
व्याख्या :
Answer: C) 52 hrs 15 min Explanation: Since they can do 19 programs in 19 hours, Then 52 programs in 52 hours respectively.And a 15 min intervalTotal time they take to do 52 programs is 52 hours 15 minutes.
प्र: Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ? 4569 05b5cc745e4d2b4197774fa5e
5b5cc745e4d2b4197774fa5e- 1140 kmstrue
- 2120 kmsfalse
- 396 kmsfalse
- 4142 kmsfalse
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उत्तर : 1. "140 kms"
व्याख्या :
Answer: A) 140 kms Explanation: It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, theDistance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 kmSo train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutesSo distance from A = Distance traveled by 2nd train in 3 hr. 30 min = 40 x 3.5 = 140 km.
प्र: Find the missing alphabet in the given sequence ? A, Z, Y, B, C, ?, W, D 4561 05b5cc718e4d2b4197774f4b3
5b5cc718e4d2b4197774f4b3- 1Efalse
- 2Zfalse
- 3Xtrue
- 4Ffalse
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उत्तर : 3. "X"
व्याख्या :
Answer: C) X Explanation: first letter A with last letter Zsimilarly 2nd last letter Y with 2nd letter BNow 3rd letter C with 3rd last letter X4th last letter W with 4th letter D and so on.... Therefore the missing letter is X
प्र: Iodine test is used to detect 4523 05b5cc699e4d2b4197774c741
5b5cc699e4d2b4197774c741- 1Carbohydratetrue
- 2Fatfalse
- 3Proteinfalse
- 4Cholesterolfalse
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उत्तर : 1. "Carbohydrate"
व्याख्या :
Answer: A) Carbohydrate Explanation: The iodine test is used to test for the presence of starch i.e, Carbohydrate.
प्र: Find the Odd One Out of the following Number Series? 3, 14, 36, 67, 113, 168 4521 05b5cc6b1e4d2b4197774d34b
5b5cc6b1e4d2b4197774d34b- 114false
- 236false
- 367true
- 4113false
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उत्तर : 3. "67"
व्याख्या :
Answer: C) 67 Explanation: Here the given number series is 3, 14, 36, 67, 113, 168 It follows a pattern that 3 3 + 1 x 11 = 3 + 11 = 14 14 + 2 x 11 = 14 + 22 = 36 36 + 3 x 11 = 36 + 33 = 69 69 + 4 x 11 = 69 + 44 = 113 113 + 5 x 11 = 113 + 55 = 168 Hence, the wrong number is 67.
प्र: Which region specializes in diamonds? 4512 05b5cc642e4d2b4197774bb4d
5b5cc642e4d2b4197774bb4d- 1Sub-Saharan Africatrue
- 2Central americafalse
- 3Middle east Europefalse
- 4South Americafalse
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उत्तर : 1. "Sub-Saharan Africa"
व्याख्या :
Answer: A) Sub-Saharan Africa Explanation:
प्र: A son and father goes for boating in river upstream . After rowing for 1 mile son notices the hat of his father falling in the river. After 5 min he tells his father that his hat has fallen. So they turn round and are able to pick the hat at the point from where they began boating after 5min. Find the speed of river in miles/hours ? 4491 05b5cc711e4d2b4197774f3d7
5b5cc711e4d2b4197774f3d7- 14 mile/hrfalse
- 26 mile/hrtrue
- 32 mile/hrfalse
- 45 mile/hrfalse
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उत्तर : 2. "6 mile/hr"
व्याख्या :
Answer: B) 6 mile/hr Explanation: Let the speed of river and boat be 'r' m/min and 'b' m/min.so relative speed in upstream (b-r)m/min and in downstream (b+r)m/min.Now in upstream distnce covered in 5 min is 5(b-r)milesso total distnce covered => 1 + 5(b-r)miles in upstreamIn downstream distance covered in 5min is 5(b+r)miles Now 1 + 5(b-r) = 5(b+r)1+5b-5r = 5b+5r1 = 10rr = 1/10 mile/min => 6 mile/hr.