IIT JEE Practice Question and Answer
8Q: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ? 2940 05b5cc75ce4d2b4197774fc2f
5b5cc75ce4d2b4197774fc2f- 1Rs.14,000false
- 2Rs.12,000true
- 3Rs. 12,800false
- 4Rs. 15,000false
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Answer : 2. "Rs.12,000"
Explanation :
Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000. Therefore, the purchase price of the machine was Rs. 12,000.
Q: How many days are there in k weeks k days ? 7876 05b5cc75ce4d2b4197774fc2a
5b5cc75ce4d2b4197774fc2a- 18+k daysfalse
- 27+1k daysfalse
- 38k daystrue
- 47/k daysfalse
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Answer : 3. "8k days"
Explanation :
Answer: C) 8k days Explanation: As we know that a week has 7 days, k weeks k days = (7k + k) days = 8k days.
Q: The calendar for the year 2007 will be the same for the year ? 1367 05b5cc75ce4d2b4197774fc25
5b5cc75ce4d2b4197774fc25- 12014false
- 22019false
- 32021false
- 42018true
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Answer : 4. "2018"
Explanation :
Answer: D) 2018 Explanation: Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day. Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017Odd day : 1 2 1 1 1 2 1 1 1 2 1 Sum = 14 odd days => 0 odd days.Calendar for the year 2018 will be the same as for the year 2007.
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2077 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: Choose what replaces '?' in the following figure ? 1380 05b5cc758e4d2b4197774fc19
5b5cc758e4d2b4197774fc19- 1Qfalse
- 2Ofalse
- 3Mfalse
- 4Ntrue
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Answer : 4. "N"
Explanation :
Answer: D) N Explanation: The alphabetical value of the letters in the left hand column follows through the sequence of Prime Numbers, with the letters in the right hand column representing the corresponding reverse alphabetical values. So, M = Reverse of M = N.
Q: If the positions of the first and the fifth digits of the number 14278359 are interchanged, similarly the positions of the second and the sixth digits are interchanged and so on, then which of the following will be the second digit from the right end after the rearrangement ? 1798 05b5cc758e4d2b4197774fc14
5b5cc758e4d2b4197774fc14- 15false
- 22true
- 37false
- 44false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given number is 14278359As given 1st and 5th digits, 2nd & 6th, 3rd & 7th and 4th & 8th digits are to to be interchanged.Therfore, the rearranged number is 83591427Then, the second digit from the right end is 2.
Q: Pradeep correctly remembers that his mother's is before twenty third February but after ninteenth February, whereas his brother correctly remembers that their mother's birthday is not on or after twentysecond February. On which day in February is definitely their mother's birthday ? 1626 05b5cc758e4d2b4197774fc0f
5b5cc758e4d2b4197774fc0f- 120 or 21true
- 220false
- 321false
- 4Nonefalse
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Answer : 1. "20 or 21"
Explanation :
Answer: A) 20 or 21 Explanation: According to Pradeep : 20,21 or 22...(1)According to his brother : not 22....(2)From (1)&(2), the birthday falls on February 20 or 21.
Q: Which of the following is the sixth to the left of the twentieth from the left end of the below arrangement ?BM%R#J@K!DF69L4*15NEP23AYQZ#7UG 1955 05b5cc758e4d2b4197774fc0a
5b5cc758e4d2b4197774fc0a- 1Ltrue
- 2Kfalse
- 34false
- 49false
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Answer : 1. "L"
Explanation :
Answer: A) L Explanation: The twentieth element in the above arrangement is 'E'.Then, the sixth element to the left of 'E' is 'L'.