GRE Practice Question and Answer
8Q: A,B,C together can do a piece of work in 10 days.All the three started workingat it together and after 4 days,A left.Then,B and C together completed the work in 10 more days.In how many days can complete a work alone ? 1507 05b5cc70ee4d2b4197774f34c
5b5cc70ee4d2b4197774f34c- 125true
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Answer : 1. "25"
Explanation :
Answer: A) 25 Explanation: (A+B+C) do 1 work in 10 days. So (A+B+C)'s 1 day work=1/10 and as they work together for 4 days so workdone by them in 4 days=4/10=2/5 Remaining work=1-2/5=3/5 (B+C) take 10 more days to complete 3/5 work. So( B+C)'s 1 day work=3/50 Now A'S 1 day work=(A+B+C)'s 1 day work - (B+C)'s 1 day work=1/10-3/50=1/25 A does 1/25 work in in 1 day Therefore 1 work in 25 days.
Q: A train covers a distance between station A and station B in 45 min.If the speed of the train is reduced by 5 km/hr,then the same distance is covered in 48 min.what is the distance between the stations A and B ? 1869 05b5cc70ee4d2b4197774f347
5b5cc70ee4d2b4197774f347- 180 kmsfalse
- 260 kmstrue
- 345 kmsfalse
- 432 kmsfalse
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Answer : 2. "60 kms"
Explanation :
Answer: B) 60 kms Explanation: Let 'd' be the distance and 's' be the speed and 't' be the timed=sxt45 mins = 3/4 hr and 48 mins = 4/5 hrAs distance is same in both cases;s(3/4) = (s-5)(4/5)3s/4 = (4s-20)/515s = 16s-80s = 80 km.=> d = 80 x 3/4 = 60 kms.
Q: A thief steals half the total number of loaves of bread plus 1/2 loaf from a bakery. A second thief steals half the remaining number of loaves plus 1/2 loaf and so on. After the 5th thief has stolen there are no more loaves left in the bakery. What was the total number of loaves did the bakery have at the beginning ? 3067 05b5cc70ee4d2b4197774f33c
5b5cc70ee4d2b4197774f33c- 121false
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Answer : 4. "31"
Explanation :
Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.
Q: Four girls Robin, Mandy, Stacy, Erica of four families Miller, Jacob, Flure and Clark prepare four salads using the fruits Apples, cherries, bananas, grapes .Each girls uses 3 fruits in her salad. No body have the same combination. 1) Robin not a Miller girl uses apples.2) Miller and Mandy uses apples and cherries. 3) Clark uses cherries and grapes but Flure uses only one of them.4) Erica is not Clark nor Flure. Question : Give all combinations of Girls with their family and salads ? 1087 05b5cc70ee4d2b4197774f341
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Answer :
Explanation :
Out of 4 fruits, any 3 are chosen by 4 families.So the combinations areApple - A Cherries - C Banana - B Grapes - G1) ACB2) ACG3) BCG4) GAB By 2nd condition, Miller family uses either i)ACB or ii)ACGNow we have Robin, Mandy and Miller who uses apples (ACB,ACG,GAB)while Miller and Mandy both uses A and C. That leaves GAB for Robin. By 3rd condition Flure uses either C or G. So if we leave out the terms containing both C and G, we are left with ACB and GAB Now, for the time being let's suppose Robin is not a Flure.So ACB is taken by Flure. So ACG has to be Miller and that leaves BCG to be Clark. So we get Robin - Jacob(GAB). By 4th and 2nd conditions Erica and Mandy belong to the first two. That leaves Stacy - Clark(BCG). By 2nd condition Mandy is not a Miller, so we get Mandy - Flure(ACB) and that leaves Erica - Miller(ACG).
Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 2597 05b5cc70ee4d2b4197774f337
5b5cc70ee4d2b4197774f337- 122/7 x 24/35true
- 222/7 x 36 x 4false
- 322/7 x 36/5false
- 422/7 x 37/21false
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Answer : 1. "22/7 x 24/35"
Explanation :
Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4. This is because of the rectangular block . Therefore , area of rectangular block immersed in water is = 227×6×6×4 Thats why portion of block immersed in water is = (22/7 * 36 * 4) / total vol. of rectangle = (22/7 * 36 * 4)/ (7*5*6) = (22/7 * 24)/ 35.
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Answer :
Explanation :
Scores of individuals : Dhoni= 80,30,10,10,1Raina=100,25,3,2,1Kholi=85,20,15,10,1Shikhar=90,20,15,3,3 Above combination satisfies all conditions given in the question. Answer 1) Raina Answer 2) Kohli and Shikhar Answer 3) Dhoni
Q: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ? 3966 05b5cc709e4d2b4197774f294
5b5cc709e4d2b4197774f294- 1Rs. 5500false
- 2Rs. 6000true
- 3Rs. 6200false
- 4Rs. 6350false
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Answer : 2. "Rs. 6000"
Explanation :
Answer: B) Rs. 6000 Explanation: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000
Q: What was the day on 2nd Jan 1901 ? 3627 05b5cc709e4d2b4197774f28f
5b5cc709e4d2b4197774f28f- 1Tuesdayfalse
- 2Wednesdaytrue
- 3Mondayfalse
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Answer : 2. "Wednesday"
Explanation :
Answer: B) Wednesday Explanation: 2nd Jan 1901 means(1900 years and 2 day)Now, 1600 years have 0 odd day300 years have 1 odd day2 days has 2 odd dayTotal no. of odd days = 0 + 1 + 2 = 3 daysHence, the day on 2nd Jan 1901 was Wednesday.