GRE Practice Question and Answer
8Q: A trader mixes 36 kg of rice at Rs. 20 per kg with 14 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is: 2196 05b5cc76ae4d2b4197774fe4a
5b5cc76ae4d2b4197774fe4a- 125%false
- 221.14%false
- 322.54%true
- 427.32%false
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Answer : 3. "22.54%"
Explanation :
Answer: C) 22.54% Explanation: C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224. S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500. Profit = 1500 - 1224 = Rs.276 Profit % = ProfitC.P×100 = 2761224×100 = 22.54%.
Q: On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ? 2193 05b5cc75ce4d2b4197774fc20
5b5cc75ce4d2b4197774fc20- 1Wednesdaytrue
- 2Tuesdayfalse
- 3Fridayfalse
- 4Thursdayfalse
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Answer : 1. "Wednesday"
Explanation :
Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Q: Which of the following pairs is mismatched? 2192 05b5cc6a8e4d2b4197774ce8b
5b5cc6a8e4d2b4197774ce8b- 1Pila globosa - pearltrue
- 2Kenia lacca - lacfalse
- 3Apis indica - honeyfalse
- 4Bombyx mori - silkfalse
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Answer : 1. "Pila globosa - pearl"
Explanation :
Answer: A) Pila globosa - pearl Explanation: Pinctada vulgaris is a bivalve from which pearl is obtained.
Q: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it? ___ utt ___ tt ___ ttu ___ 2190 05b5cc6f1e4d2b4197774ef59
5b5cc6f1e4d2b4197774ef59- 1t t u tfalse
- 2t u t tfalse
- 3t u u ttrue
- 4t t t ufalse
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Answer : 3. "t u u t"
Explanation :
Answer: C) t u u t Explanation: t, u, u and t. The sequence is : tut tut tut tut.
Q: What travels around the world and stays in one spot? 2183 05b5cc64de4d2b4197774bc93
5b5cc64de4d2b4197774bc93- 1Slippersfalse
- 2Walking stickfalse
- 3Stampstrue
- 4None of the abovefalse
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Answer : 3. "Stamps"
Explanation :
Answer: C) Stamps Explanation: Stamps are what travel around the worldstaying in one spot. Slippers and walking stick can also travel around the world but they will not stay at one spot. So they are eliminated.
Q: How much does a clock lose per day, if its hands coincide ever 65 minutes ? 2179 05b5cc6f8e4d2b4197774f077
5b5cc6f8e4d2b4197774f077- 11440/143 minfalse
- 2184/13 minfalse
- 31425/18 mintrue
- 4541/9 minfalse
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Answer : 3. "1425/18 min"
Explanation :
Answer: C) 1425/18 min Explanation: 55 min. spaces are covered in 60 min.60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.Loss in 65 min. = (720/11 - 65 ) = 5/11Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
Q: An intelligent boy is doing a jigsaw with 275 pieces. Each day that he fits pieces together there are fewer pieces left, and it is reasonable to assume that he fits more pieces each day because the number left to sort out diminishes progressively. Hence he is able to fit an extra piece as each day goes by. On the first day he fits 20 pieces. How many days does it take for him to complete the puzzle ? 2177 05b5cc71ee4d2b4197774f59a
5b5cc71ee4d2b4197774f59a- 111 daystrue
- 215 daysfalse
- 313 daysfalse
- 416 daysfalse
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Answer : 1. "11 days"
Explanation :
Answer: A) 11 days Explanation: Let 'n' number of days it take to complete. we know that sum of n number= n/2[2a+(n-1)d]where a=20,d=1;n/2[2x20+(n-1)1]=275n[n+39]=550n2 + 39n - 550 = 0 n2+ 50n - 11n - 550 = 0(n-11) (n-50) = 0n-11 = 0;n = 11(Days).
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2177 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.