Answer: D) Rs. 1250 Explanation: 2500 in 5th year and 3000 in 7th year So in between 2 years Rs. 500 is increased => for a year 500/2 = 250So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250Hence, the initial amount must be 2500 - 1250 = Rs. 1250

Answer: D) 8 Explanation: 9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie., (1+1) x (1+1) x (1+1)= 8 ; we get eight factors.

Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.

Answer: B) 1243 Explanation: Given number sequence is 28, 16, 28, 76, 274 Here the sequence follows a pattern that 28 28 x 0.5 + 2 = 14 + 2 = 16 16 x 1.5 + 4 = 24 + 4 = 28 28 x 2.5 + 6 = 70 + 6 = 76 76 x 3.5 + 8 = 266 + 8 = 274 274 x 4.5 + 10 = 1233 + 10 = 1243   Hence, the next number in the given number sequence is 1243.

Answer: D) Grand-mother Explanation: My father's brother's only sibling is my father. My father's mother is my grandmother. My sister's only brother is myself. So she is my Grandmother.

Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172,  OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504

Answer: B) J, L Explanation: This question concerns a committee’s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced. The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced: Reduced         ::      K, NNot reduced   ::      J The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we’ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced: Reduced        ::      K, NNot reduced  ::      J, L Answer choice (B) is therefore the correct answer.

Answer: C) 10 years Explanation: Let the age of the daughter today be ‘x’ years. Mother’s age today = 3x years After 10 years, we have 3x + 10 = 2(x + 10) x = 10 years.