GRE Practice Question and Answer
8Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 3725 05b5cc715e4d2b4197774f463
5b5cc715e4d2b4197774f463- 17 : 12false
- 28 : 13true
- 39 : 4false
- 42 : 5false
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Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13
Q: Who set up the world's first floating ATM ? 3724 05b5cc711e4d2b4197774f3f5
5b5cc711e4d2b4197774f3f5- 1Bank of Americafalse
- 2Barclays Bankfalse
- 3Axis Bankfalse
- 4State Bank of Indiatrue
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Answer : 4. "State Bank of India"
Explanation :
Answer: D) State Bank of India Explanation: India's banking behemoth -- the State Bank of India -- has set up the world's first-ever floating ATM on a boat in Kerala. The boat with the ATM on board will berth at jetties in Kerala's huge backwaters through which thousands of people travel daily.
Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 3714 05b5cc70ee4d2b4197774f380
5b5cc70ee4d2b4197774f380- 1Afalse
- 2Bfalse
- 3Ctrue
- 4Dfalse
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Answer : 3. "C"
Explanation :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C
Q: Read the arrangement carefully and give the answer of following questions ? K$23DBE8HM4@5JF4%K1+WR#AA*415 How many such symbols are there which is not immediately preceded by a letter but immediately followed by a number ? 3701 05b5cc6c5e4d2b4197774dd4b
5b5cc6c5e4d2b4197774dd4b- 11true
- 22false
- 33false
- 40false
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Answer : 1. "1"
Explanation :
Answer: A) 1 Explanation: Only one such symbol is there in the given arrangement. It is 4@5.
Q: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 3700 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
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Answer : 4. "E = 4 & Y = 2"
Explanation :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3680 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
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Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 3623 05b5cc75ee4d2b4197774fcca
5b5cc75ee4d2b4197774fcca- 170 yearsfalse
- 230 yearstrue
- 360 yearsfalse
- 440 yearsfalse
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Answer : 2. "30 years"
Explanation :
Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.
Q: John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ? 3606 05b5cc75ce4d2b4197774fc84
5b5cc75ce4d2b4197774fc84- 1Rs.16,500false
- 2Rs.17,500true
- 3Rs.14,200false
- 4Rs.15,520false
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Answer : 2. "Rs.17,500"
Explanation :
Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% => Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.