GRE Practice Question and Answer
8Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3545 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 3535 05b5cc715e4d2b4197774f463
5b5cc715e4d2b4197774f463- 17 : 12false
- 28 : 13true
- 39 : 4false
- 42 : 5false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13
Q: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 3506 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "E = 4 & Y = 2"
Explanation :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
Q: The number of ways in which 8 distinct toys can be distributed among 5 children? 3475 05b5cc699e4d2b4197774c700
5b5cc699e4d2b4197774c700- 15P8false
- 25^8true
- 38P5false
- 48^5false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "5^8"
Explanation :
Answer: B) 5^8 Explanation: As the toys are distinct and not identical, For each of the 8 toys, we have three choices as to which child will receive the toy. Therefore, there are 58 ways to distribute the toys. Hence, it is 58 and not 85.
Q: Find the missing number in the given series ? 15, 51, 216, 1100, ?, 46452 3473 05b5cc74ae4d2b4197774faa9
5b5cc74ae4d2b4197774faa9- 15660false
- 26560false
- 36750false
- 46630true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "6630"
Explanation :
Answer: D) 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer :
Explanation :
1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.
Q: At 6′o clock a clock ticks 6 times. The time between first and last ticks is 30 seconds. How long does it tick at 12′o clock ? 3425 05b5cc731e4d2b4197774f7ec
5b5cc731e4d2b4197774f7ec- 166 sectrue
- 255 secfalse
- 336 secfalse
- 424 secfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "66 sec"
Explanation :
Answer: A) 66 sec Explanation: For ticking 6 times, there are 5 intervals. Each interval has time duration of 30/5 = 6 secs At 12 o'clock, there are 11 intervals,so total time for 11 intervals = 11 x 6 = 66 secs.
Q: John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ? 3417 05b5cc75ce4d2b4197774fc84
5b5cc75ce4d2b4197774fc84- 1Rs.16,500false
- 2Rs.17,500true
- 3Rs.14,200false
- 4Rs.15,520false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs.17,500"
Explanation :
Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% => Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.