GATE Practice Question and Answer
8Q: At what time will B catch up with A, if A starts from a place at 11.00 A.M. and travels at a speed of 3.5 kmph, B starts at 1.00 P.M. and travels with speeds of 1 kmph for 1 hour, 2 kmph for the next 1 hour, 3 kmph for the next 1 hour and so on. 2352 05b5cc715e4d2b4197774f409
5b5cc715e4d2b4197774f409- 18 : 47 pmfalse
- 26 : 40 pmfalse
- 38 : 42 pmfalse
- 47 : 40 pmtrue
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Answer : 4. "7 : 40 pm"
Explanation :
Answer: D) 7 : 40 pm Explanation: At 1 pm ... Distance between A and B = 2x3.5 = 7 kmsat 2 pm .....Distance between A and B = 7 + 3.5 - 1 = 9.5 kmsAt 3 pm ....Distance between A and B = 9.5 + 3.5 - 2 = 11 kms.......At 7 pm distance between A and B = 3 kms.From 7 pm to 8 pm, speed of A = 3.5 kmphspeed of B = 8 kmphRelative speed = 4.5 kmph Time taken by B to meet A = 3/4.5 hrs = 30/45 hrs = 120/3 mins = 40 mins. So meeting time is 7 : 40 PM.
Q: What is the next number of the following sequence ? 21, 77, 165, 285, ...... 2343 05b5cc74ae4d2b4197774fab8
5b5cc74ae4d2b4197774fab8- 1404false
- 2415false
- 3426false
- 4437true
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Answer : 4. "437"
Explanation :
Answer: D) 437 Explanation: The series follow the rule, 21 = 77 = 92-4165 = 132-4285 = 172-4 5,9,13,17,21,(+4)...In the same way next no. will be 212-4 = 441 - 4 = 437
Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2343 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ? 2336 05b5cc736e4d2b4197774f87e
5b5cc736e4d2b4197774f87e- 155 kmstrue
- 235 kmsfalse
- 325 kmsfalse
- 465 kmsfalse
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Answer : 1. "55 kms"
Explanation :
Answer: A) 55 kms Explanation: Let x and y be the respective km's travelled by man via taxi and by his own car.Given x + y = 90 => x = 90 - yBut according to the question,7x + 6y = 5957(90-y) + 6y = 595=> 630 - 7y + 6y = 595=> y = 630 - 595 = 35=> x = 90 - 35 = 55Therefore, the distance travelled by taxi is 55 kms.
Q: एक पर्सनल कंप्यूटर की शब्द लंबाई है 2334 05b5cc642e4d2b4197774bb7c
5b5cc642e4d2b4197774bb7c- 132 bitfalse
- 216 bitfalse
- 38 bittrue
- 44 bitfalse
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Answer : 3. "8 bit"
Explanation :
Answer: C) 8 bit व्याख्या: शब्द की लंबाई कंप्यूटर के सीपीयू द्वारा एक बार में संसाधित बिट्स की संख्या को संदर्भित करती है। इन दिनों, आमतौर पर 32 बिट या 64 बिट का उपयोग किया जाता है। डेटा बस आकार, निर्देश आकार, पता आकार आमतौर पर शब्द आकार के गुणक होते हैं।
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2334 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together ? 2332 05b5cc6d8e4d2b4197774e737
5b5cc6d8e4d2b4197774e737- 15 (2/3)false
- 26 (3/4 )false
- 34 (1/2)true
- 43false
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Answer : 3. "4 (1/2)"
Explanation :
Answer: C) 4 (1/2) Explanation: Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total. Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 They would take 9/2 days = 4 (1/2) days to complete the work working together.
Q: Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ? 2330 05b5cc6d8e4d2b4197774e7c6
5b5cc6d8e4d2b4197774e7c6- 1360 mfalse
- 2420 mtrue
- 3460 mfalse
- 4320 mfalse
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Answer : 2. "420 m"
Explanation :
Answer: B) 420 m Explanation: Let the length of the stationary train Y be LY Given that length of train X, LX = 300 m Let the speed of Train X be V. Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively. => 300/V = 25 ---> ( 1 ) (300 + LY) / V = 60 ---> ( 2 ) From (1) V = 300/25 = 12 m/sec. From (2) (300 + LY)/12 = 60 => 300 + LY = 60 (12) = 720 => LY = 720 - 300 = 420 m Length of the stationary train = 420 m