GATE Practice Question and Answer

Q: What word in the English language is always spelled incorrectly? 3440 0

  • 1
    Schezwan
    Correct
    Wrong
  • 2
    Yorker
    Correct
    Wrong
  • 3
    Incorrectly
    Correct
    Wrong
  • 4
    Psycologically
    Correct
    Wrong
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Answer : 3. "Incorrectly"
Explanation :

Answer: C) Incorrectly Explanation: INCORRECTLY is the only English word which is always spelled incorrectly.

Q: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current  ? 3428 0

  • 1
    1 kmph
    Correct
    Wrong
  • 2
    3.2 kmph
    Correct
    Wrong
  • 3
    1.5 kmph
    Correct
    Wrong
  • 4
    2 kmph
    Correct
    Wrong
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Answer : 3. "1.5 kmph"
Explanation :

Answer: C) 1.5 kmph Explanation: 72 --- 9 ? ---- 1 => Down Stream = 8 45 ---- 9 ? ---- 1 => Up Stream = 5 Speed od current S = ? S = (8 - 5)/2 = 1.5 kmph.

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Answer : 2. "Rs.17,500"
Explanation :

Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% =>  Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.

Q: At 6′o clock a clock ticks 6 times. The time between first and last ticks is 30 seconds. How long does it tick at 12′o clock ? 3425 0

  • 1
    66 sec
    Correct
    Wrong
  • 2
    55 sec
    Correct
    Wrong
  • 3
    36 sec
    Correct
    Wrong
  • 4
    24 sec
    Correct
    Wrong
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Answer : 1. "66 sec"
Explanation :

Answer: A) 66 sec Explanation: For ticking 6 times, there are 5 intervals. Each interval has time duration of 30/5 = 6 secs At 12 o'clock, there are 11 intervals,so total time for 11 intervals = 11 x 6 = 66 secs.

Q: Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is  ? 3410 0

  • 1
    3 : 4
    Correct
    Wrong
  • 2
    4 : 3
    Correct
    Wrong
  • 3
    2 : 3
    Correct
    Wrong
  • 4
    3 : 2
    Correct
    Wrong
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Answer : 2. "4 : 3"
Explanation :

Answer: B) 4 : 3 Explanation: Let us name the trains as A and B. Then, (A's speed) : (B's speed) = √b : √a = √16 : √9 = 4:3

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Answer : 4. "Rs. 1,00,000"
Explanation :

Answer: D) Rs. 1,00,000 Explanation: Deepa invested Rs.50,000 for 12 months, Rs.(50000 + 20000) for 12 months and Rs.(50000 + 20000 + 20000) for 12 months.i.e, she invested Rs.50,000 for 12 months, Rs.70000 for 12 months and Rs.90000 for 12 months.Sushma invested Rs. 70000 for 2 years; i.e, Rs.70000 for 24 monthsAnd, Avanthi invested Rs.70000 for 1 year; i.e, Rs. 70000 for 12 months. Their investing ratio:Deepa : Sushma : Avanthi = (50,000 x 12 + 70000 x 12 + 90000 x 12):(70000 x 24):(70000 x 12)= (25,20,000):(16,80,000):(8,40,000) = 252:168:84 = 3:2:1 Total profit for 3 years = Rs.3,00,000Therefore, Sushma's share = Rs.(3,00,000 x 2 /(3+2+1)) = Rs.(3,00,000 x 2/6) = Rs.1,00,000.

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Answer : 3. "16/25"
Explanation :

Answer: C) 16/25 Explanation: If there are total 100 candidates, 40 candidates are really capable and 60 candidates are incapable.Of the candidates who are really capable = 80% 40*(80/100)=32 pass the test andof the incapable= 30%60*(30/100)=18 pass the test.Total candidates who passed the test = 32+18 = 50The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

Q: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ? 3396 0

  • 1
    Rs. 500
    Correct
    Wrong
  • 2
    Rs. 245
    Correct
    Wrong
  • 3
    Rs. 1250
    Correct
    Wrong
  • 4
    Rs. 635
    Correct
    Wrong
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Answer : 1. "Rs. 500"
Explanation :

Answer: A) Rs. 500 Explanation: (kx5x1)/100 + [(1500 - k)x6x1]/100 = 85 5k/100 + 90 – 6k/100 = 85 k/100 = 5 => k = 500

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