GATE प्रश्न और उत्तर का अभ्यास करें

प्र: "Good Samaritan Policy" has been launched by which state / union territory government? 4103 0

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    Delhi
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  • 2
    Karnataka
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  • 3
    Telangana
    सही
    गलत
  • 4
    Gujarath
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उत्तर : 1. "Delhi"
व्याख्या :

Answer: A) Delhi Explanation: The Delhi government has recently approved 'Good Samaritan Policy' under which monetary incentive of Rs 2,000 and appreciation certificate will be given to people who help road accident victims in the national capital. The scheme is intended to encourage people to take accident victims in emergency situation to hospitals so that someone’s life could be saved.

प्र: A can write 32 pages in 6 hours and B can write 40 pages in 5 hours. If they write together, in how many hours they can write 110 pages ? 4097 0

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    7 hrs
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  • 2
    6 hrs 10 min
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  • 3
    5 hrs 25min
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  • 4
    8 hrs 15 min
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उत्तर : 4. "8 hrs 15 min"
व्याख्या :

Answer: D) 8 hrs 15 min Explanation: A can write in 1hour = 32/6 pages Similarly, B in 1 hour = 40/5 pages Together (A+B) in 1 hour = 32/6 + 40/5 = 40/3 So, A+B write 40/3 pages in 1 hour A+B write 110 pages in (3/40) x 110 Hours = 8 hours 15 min.

प्र: In a mens hostel, there were 95 students. To accommodate 30 more students the average is decreased by rupees 5. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now ? 4093 0

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    Rs. 4680
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  • 2
    Rs. 4420
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  • 3
    Rs. 4960
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  • 4
    Rs. 5480
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उत्तर : 1. "Rs. 4680"
व्याख्या :

Answer: A) Rs. 4680 Explanation: Let the expenditure on the 95 students be 'x' Then, 95x + 500 = 120(x – 5)95x + 500 = 120x - 600120x - 95x = 110025x = 1100=> x = 44 Therefore, total expenditure of the hostel becomes95 x 44 + 500 = 4680.

प्र: In a certain code language, 'how can you go' is written as 'ja da ka pa', 'can you come here' is written as 'na ka sa ja' and 'cone and go' is written as 'ra pa sa'. How is 'here' written in that code ? 4089 0

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    na
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  • 2
    ja
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  • 3
    sa
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  • 4
    None
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उत्तर : 1. "na"
व्याख्या :

Answer: A) na Explanation: From the given information : how can you go = ja da ka pa....(1)can you come here = na ka sa ja...(2)come and go = ra pa sa....(3)from (1)&(2), can you = ja ka...(4)from (2)&(3), come = sa...(5)Using (4)&(5) in (2), we get here = na.

प्र: The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest) 4072 0

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    19 years
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  • 2
    16 years
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  • 3
    18 years
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  • 4
    20 years
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उत्तर : 4. "20 years"
व्याख्या :

Answer: D) 20 years Explanation: Present total age of the members = 26(5) = 130 years.   Present age of the youngest member = 10 years   Present total age of the remaining four members = 130 -10 = 120 years   Their average age at the time of the birth of the youngest member = 120-4×104 = 30 - 10 = 20 years.

प्र: Central processing unit is combination of 4029 0

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    Arithmetic and Control unit
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  • 2
    Control and Output unit
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  • 3
    Control and Storage unit
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    गलत
  • 4
    Arithmetic logic and input unit
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उत्तर : 1. "Arithmetic and Control unit"
व्याख्या :

Answer: A) Arithmetic and Control unit Explanation:

प्र: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 4015 0

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    A gain of Rs. 27
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  • 2
    A loss of Rs. 37
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  • 3
    A loss of Rs. 27
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  • 4
    A gain of Rs. 37
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उत्तर : 2. "A loss of Rs. 37"
व्याख्या :

Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is:  64 − 27 = 37 A loss of Rs.37

प्र: In an objective competitive exam, a correct answer score 4 marks and on a wrong answer 2 marks are negatively added. A student scores 420 marks from 150 question. How many answers were correct ? 4015 0

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    145
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  • 2
    138
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  • 3
    125
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  • 4
    120
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उत्तर : 4. "120"
व्याख्या :

Answer: D) 120 Explanation: let x be the correct answer and y be the wrong answerso the total number of questions is (x + y) = 150.....(1)=> 4x - 2y = 420.....(2)By solving (1) & (2), we get => 6x = 720hence x = 120Therefore, number of correct answers are 120.

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