Answer: D) Rs. 1250 Explanation: 2500 in 5th year and 3000 in 7th year So in between 2 years Rs. 500 is increased => for a year 500/2 = 250So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250Hence, the initial amount must be 2500 - 1250 = Rs. 1250

Answer: B) P Explanation: From the given information, the sitting arrangement can be  P-Q-W-S-U-V-T-R  i.e. in circular as From the above figure it is clear that opposite to U is P.

Answer: A) 56 Explanation: If we count letters till the end of the alphabet including that letter in reverse order then Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1G = 20 and O = 12 totaling 32S = 8, H = 19 and E = 22 totaling 49 So SOME = 8 + 12 + 14 + 22 = 56.

Answer: C) impasse Explanation: Impasse means, a situation in which no progress is possible, especially because of disagreement; a deadlock. So it is Impasse.

Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers

Answer: A) Grand father Explanation: Q's mother is sister of P and daughter of M => P is the child of M.S is daughter of P and sister of T, so P is parent of T too.M ----> parent --------> P ------------>parent -------------> TBut given M is brother of R => M is male. So, M is grandfather of T.

Answer: B) 26.166 minutes Explanation: Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120 For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120 So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120 So remaining tank = 13/120 Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes   Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

Answer: C) [6 + (261/315)] days Explanation: After day 1, A finishes 1/9 of the work. After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished. After day 3, C finishes 1/5 more of total work. Total finished is 143/315. So, after day 6, total work finished is 286/315.   Now remaining work =  29 /315   On day 7, A will work again    Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.   Since he takes 9 days to finish the total task, he will need 261/315 of the day.    Total days required is 6 + (261/315) days.