CAT प्रश्न और उत्तर का अभ्यास करें
8प्र: Find the odd one out of the following options. 3209 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
- उत्तर देखें
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- SingleChoice
उत्तर : 4. "Granite"
व्याख्या :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.
प्र: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3208 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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उत्तर : 3. "3:2"
व्याख्या :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.
प्र: The wildcard in a WHERE clause is useful when 3204 05b5cc65ee4d2b4197774be3b
5b5cc65ee4d2b4197774be3b- 1An exact match is not possible in a SELECT statement.true
- 2An exact match is necessary in a CREATE statement.false
- 3An exact match is not possible in a CREATE statement.false
- 4An exact match is necessary in a SELECT statement.false
- उत्तर देखें
- Workspace
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उत्तर : 1. "An exact match is not possible in a SELECT statement."
व्याख्या :
Answer: A) An exact match is not possible in a SELECT statement. Explanation:
प्र: Fumble is to Finesse as Malign is to 3199 05b5cc6a2e4d2b4197774cba8
5b5cc6a2e4d2b4197774cba8- 1Slanderfalse
- 2Extoltrue
- 3Criticizefalse
- 4Assurancefalse
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- Workspace
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उत्तर : 2. "Extol"
व्याख्या :
Answer: B) Extol Explanation: Fumble means grope, mishandle, drop, mistake, blunder, bungle. Finesse means skill, grace, elegance, assurance, diplomacy, discretion. So, they are opposites. Similarly, Malign means slander or criticize. Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns. Extol means praise or exalt, benevolence
प्र: How is my father's brother's only sibling's mother related to my sister's only brother ? 3196 05b5cc6e1e4d2b4197774ebc0
5b5cc6e1e4d2b4197774ebc0- 1Neicefalse
- 2Auntfalse
- 3Motherfalse
- 4Grand-mothertrue
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उत्तर : 4. "Grand-mother"
व्याख्या :
Answer: D) Grand-mother Explanation: My father's brother's only sibling is my father. My father's mother is my grandmother. My sister's only brother is myself. So she is my Grandmother.
प्र: If NAMO = 172 and OM = 56 then, SHIVAY = ? 3192 05b5cc6cee4d2b4197774e237
5b5cc6cee4d2b4197774e237- 1606false
- 2415false
- 3504true
- 4404false
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उत्तर : 3. "504"
व्याख्या :
Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172, OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504
प्र: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ? 3181 05b5cc75ce4d2b4197774fc2f
5b5cc75ce4d2b4197774fc2f- 1Rs.14,000false
- 2Rs.12,000true
- 3Rs. 12,800false
- 4Rs. 15,000false
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उत्तर : 2. "Rs.12,000"
व्याख्या :
Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000. Therefore, the purchase price of the machine was Rs. 12,000.
प्र: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3178 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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- Workspace
- SingleChoice
उत्तर : 1. "127.5 m"
व्याख्या :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.