CAT Practice Question and Answer
8Q: Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ? 5242 05b5cc6d6e4d2b4197774e66a
5b5cc6d6e4d2b4197774e66a- 14 daysfalse
- 28 daysfalse
- 33 daysfalse
- 46 daystrue
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Answer : 4. "6 days"
Explanation :
Answer: D) 6 days Explanation: 4/10 + 9/x = 1 => x = 15 Then both can do in 1/10 + 1/15 = 1/6 => 6 days
Q: Who translated Ramayana into Persian? 5222 05b5cc675e4d2b4197774c139
5b5cc675e4d2b4197774c139- 1Abdul Fazitrue
- 2Badaunifalse
- 3Isar Dasfalse
- 4Abdul Latiffalse
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Answer : 1. "Abdul Fazi"
Explanation :
Answer: A) Abdul Fazi Explanation: In 1574 Akbar started a Maktab Khana or a house of translation works in Fatehpur Sikri. He endorsed the work to a few officials to make translations of the Sanskrit books Rajatarangini, Ramayana and Mahabharata into the Persian language. In that officials, Abdul Fazi translated Ramayana into Persian.
Q: Find the odd number out of the following number series? 2 4 8 11.5 18.25 28.375 5218 05b5cc68be4d2b4197774c380
5b5cc68be4d2b4197774c380- 118.25false
- 228.375false
- 311.5false
- 48true
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Answer : 4. "8"
Explanation :
Answer: D) 8 Explanation: Given number series follows a pattern that, 2 2 x 1.5 + 1 = 4 4 x 1.5 + 1 = 7 (not equal to 8) 7 x 1.5 + 1 = 11.5 11.5 x 1.5 + 1 = 18.25 18.25 x 1.5 + 1 = 28.375 Hence, the odd number in the given number series is 8.
Q: Microprocessors as switching devices are for which generation computers? 5217 05b5cc645e4d2b4197774bbb4
5b5cc645e4d2b4197774bbb4- 1Fourth generationtrue
- 2Third generationfalse
- 3Second generationfalse
- 4First generationfalse
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Answer : 1. "Fourth generation"
Explanation :
Answer: A) Fourth generation Explanation: Microprocessors are used in the computers of fourth generation computers. Personal microcomputers were possible due to the microprocessors. Microprocessors further revolutionized the development of computers. The first microprocessor called Intel 4004 was developed by American Intel Corporation in 1971.
Q: A person takes 20 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed ? 5161 05b5cc6eee4d2b4197774eebe
5b5cc6eee4d2b4197774eebe- 11hrfalse
- 21 hr 20 mintrue
- 31 hr 10 minfalse
- 450 minfalse
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Answer : 2. "1 hr 20 min"
Explanation :
Answer: B) 1 hr 20 min Explanation: Let the distance and original speed be 'd' km and 'k' kmph respectively. d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3 => (5d - 4d)/4k = 1/3 => d = 4/3 k Time taken to cover the distance at original speed = d/k = 4/3 hours = 1 hour 20 minutes.
Q: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a girl sitting at window seat in the slower train in 32 seconds. Find the length of the faster train ? 5152 05b5cc6d8e4d2b4197774e769
5b5cc6d8e4d2b4197774e769- 1170 mfalse
- 2100 mfalse
- 3270 mfalse
- 4320 mtrue
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Answer : 4. "320 m"
Explanation :
Answer: D) 320 m Explanation: Relative speed = (72 - 36) x 5/18 = 2 x 5 = 10 mps.Distance covered in 32 sec = 32 x 10 = 320 m. The length of the faster train = 320 m.
Q: Find the next number in the series 3, 4, 5, 5, 12, 13, 7, 24, 25, 8, 15, ... 5148 05b5cc771e4d2b4197774ffc6
5b5cc771e4d2b4197774ffc6- 126false
- 216false
- 317true
- 418false
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Answer : 3. "17"
Explanation :
Answer: C) 17 Explanation: The pattern is 32+42=52, 52+122=132, 72+242=252 The next number = 82+152=172 i.e. 17
Q: The average weight of 45 passengers in a bus is 52 kg. 5 of them whose average weight is 48 kg leave the bus and other 5 passengers whose average weight is 54 kg join the bus at the same stop. What is the new average weight of the bus? 5133 05b5cc6abe4d2b4197774d06c
5b5cc6abe4d2b4197774d06c- 154.21 kgsfalse
- 251.07 kgsfalse
- 352.66 kgstrue
- 453.45 kgsfalse
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Answer : 3. "52.66 kgs"
Explanation :
Answer: C) 52.66 kgs Explanation: Given total number of passengers in the bus = 45 First average weight of 45 passengers = 52 kgs Average weight of 5 passengers who leave bus = 48 Average weight of 5 passengers who joined the bus = 54 Therefore, the net average weight of the bus is given by = 45 x 52 - 5 x 48 + 5 x 5445 = 237045= 1583= 52.66 kgs.