Answer: A) 450.187 Explanation: Pattern is 3 3 x 3.5 = 10.5 10.5 x 3.5 = 36.75 36.75 x 3.5 = 128.625 128.625 x 3.5 = 450.187

Answer: A) 35 Explanation: Here the given number series is 0, 3, 8, 15, 24, ? The next number in the given series can be found such a way that the number series follows a pattern, 22 - 4 = 032 - 6 = 342  - 8 = 852 - 10 = 1562 - 12 = 2472 - 14 = 35Hence, the next number in the iven series is 35.

Answer: D) P.S. Krishnan Explanation:

Answer: C) 18.5 Explanation: The given series pattern follows   17       9       10       18.5       35       90   × 0.5 + 0.5,   × 1 + 1,   × 1.5 + 1.5,   × 2 + 2,   × 2.5 + 2.5   So here    17x0.5 + 0.5 = 9   9x1 + 1 = 10   10x1.5 + 1.5 = 16.5   16.5x2 + 2 = 35   35x2.5 + 2.5 = 90   Here the odd man in the given series is 18.5

Answer: B) 63 Explanation: Here the series follows the pattern that, product of succesive prime numbers i.e,  2 × 3 = 6  3 × 5 = 15  5 × 7 = 35  7 × 11 = 77  11 × 13 = 143  13 × 17 = 221  17 × 19 = 323 So here in place of 77 the number 63 is written. So the wrong number is 63.

Answer: C) 81 Explanation: The series follows the following pattern.   4   16 = 42   37 = 12+62   58 = 32+72   81 ≠52+82.   Here every number is based on the digits of previous number. Hence, 81 is the wrong number in the given series.

Answer: B) 7.5 Explanation: The given number series follows a pattern that 11 11 - 5.5 = 5.5 5.5 + 4.5 = 10 10 - 3.5 = 6.5 6.5 + 2.5 = 9 9 - 1.5 = 7.5   Hence, the next number in the given number series is 7.5.

Answer: B) 1962 Explanation: Arithmetic Series ::   An Arithmetic Series is a series of numbers in which each term increases by a constant amount.   How to find the sum of the Arithmetic Sequence or Series for the given Series ::   When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence.   That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term   Here Last term is given by an = a1 + n-1d where d = common difference   Now given Arithmetic Series is    2, 5, 8, 11,...   Here a1 = 2,  d = 3, n = 36    Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107    Now, Sum to 36 terms is given by   S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962       Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.