Books and Authors Practice Question and Answer
8Q: Who is the author of the book "The Hungry Tide"? 806 05b5cc6b1e4d2b4197774d313
5b5cc6b1e4d2b4197774d313- 1Mitali Meelanfalse
- 2Ravinder Singhfalse
- 3Amitav Ghoshtrue
- 4Sudha Murtyfalse
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Answer : 3. "Amitav Ghosh"
Explanation :
Answer: C) Amitav Ghosh Explanation:
Q: Find the Odd One Out? 3, 4, 14, 48, 576, 27648 1586 05b5cc6b0e4d2b4197774d2c6
5b5cc6b0e4d2b4197774d2c6- 14false
- 214true
- 348false
- 427648false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: Given Number series is : 3 4 14 48 576 27648 It follows a pattern that, 3 4 4 x 3 = 12 but not 14 12 x 4 = 48 48 x 12 = 576 576 x 48 = 27648 Hence, the odd one in the given Number Series is 14.
Q: Find the missing number? 15, 30, ? , 40, 8, 48 6563 05b5cc6afe4d2b4197774d264
5b5cc6afe4d2b4197774d264- 121false
- 28false
- 319false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Given nuber series is 15, 30, ? , 40, 8, 48 Here the number series follows a pattern that 15 15 x 2 = 30 30 ÷ 3 = 10 10 x 4 = 40 40 ÷ 5 = 8 8 x 6 = 48 Hence, the missing number in the series is 10.
Q: Find the sum of the Arithmetic Series upto 36 terms 2, 5, 8, 11,... 1332 15b5cc6afe4d2b4197774d259
5b5cc6afe4d2b4197774d259- 13924false
- 21962true
- 31684false
- 41452false
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Answer : 2. "1962"
Explanation :
Answer: B) 1962 Explanation: Arithmetic Series :: An Arithmetic Series is a series of numbers in which each term increases by a constant amount. How to find the sum of the Arithmetic Sequence or Series for the given Series :: When the series contains a large amount of numbers, its impractical to add manually. You can quickly find the sum of any arithmetic sequence by multiplying the average of the first and last term by the number of terms in the sequence. That is given by Sn = n(a1 + an)2 Where n = number of terms, a1 = first term, an = last term Here Last term is given by an = a1 + n-1d where d = common difference Now given Arithmetic Series is 2, 5, 8, 11,... Here a1 = 2, d = 3, n = 36 Now, an= a1 + n - 1d a36= 2 + 36 - 13 = 105 + 2 = 107 Now, Sum to 36 terms is given by S36 = 36(2 + 107)2 = 36 x 1092 = 39242 = 1962 Therefore, Sum to 36 terms of the series 2, 5, 8, 11,... is 1962.
Q: Find the missing number in the series 1, 6, ?, 15, 45, 66, 91 1984 15b5cc6afe4d2b4197774d230
5b5cc6afe4d2b4197774d230- 124false
- 228true
- 332false
- 426false
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Answer : 2. "28"
Explanation :
Answer: B) 28 Explanation: Here the given series 1, 6, ?, 15, 45, 66, 91 follows a Pattern in the series is, +5, +9, +13,...,.. +21, +25 So +4 is getting increased at every term addition. Missing Number in the series will be 15+(9+4) = 15 + 13 = 28.
Q: What comes next in this sequence 196, 169, 144, 121, 100, 81, ? 1626 05b5cc6ade4d2b4197774d13e
5b5cc6ade4d2b4197774d13e- 177false
- 274false
- 367false
- 464true
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Answer : 4. "64"
Explanation :
Answer: D) 64 Explanation: The given number series follows a pattern that 196, 169, 144, 121, 100, 81, ? -27 -25 -23 -21 -19 -17 => 81 - 17 = 64 Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
Q: 7, 11, 19, 35, ? Find the next number in the given number series? 1919 05b5cc6ace4d2b4197774d0bb
5b5cc6ace4d2b4197774d0bb- 1131false
- 294false
- 383false
- 467true
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Answer : 4. "67"
Explanation :
Answer: D) 67 Explanation: Here the given series 7, 11, 19, 35, ? follows a pattern that (x 2 - 3) i.e, 7 7 x 2 - 3 = 11 11 x 2 - 3 = 19 19 x 2 - 3 = 35 35 x 2 - 3 = 67 67 x 2 - 3 = 131 Hence the next number in the given number series is 67.
Q: Find the missing number? 5 19 49 101 181 295 ? 4801 05b5cc6abe4d2b4197774cff2
5b5cc6abe4d2b4197774cff2- 1401false
- 2351false
- 3449true
- 4501false
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Answer : 3. "449"
Explanation :
Answer: C) 449 Explanation: Given number series is 5 19 49 101 181 295 ? Here the series follows pattern that 5 19 49 101 181 295 ? 14 30 52 80 114 (difference) 16 22 28 34 (difference) 6 6 6 (Common difference) Therefore, the missing number in the series is ? = 295 + 115 + 34 + 6 = 449.