Aptitude Questions Practice Question and Answer

Q: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 2466 1

  • 1
    Rs. 175
    Correct
    Wrong
  • 2
    Rs. 325
    Correct
    Wrong
  • 3
    Rs. 340
    Correct
    Wrong
  • 4
    Rs. 260
    Correct
    Wrong
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Answer : 3. "Rs. 340"
Explanation :

Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.

Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 1734 1

  • 1
    42.2 mts
    Correct
    Wrong
  • 2
    33.45 mts
    Correct
    Wrong
  • 3
    66.6 mts
    Correct
    Wrong
  • 4
    58.78 mts
    Correct
    Wrong
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Answer : 3. "66.6 mts"
Explanation :

Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.

Q: If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ? 1909 0

  • 1
    78 paise
    Correct
    Wrong
  • 2
    48 paise
    Correct
    Wrong
  • 3
    54 paise
    Correct
    Wrong
  • 4
    62 paise
    Correct
    Wrong
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Answer : 2. "48 paise"
Explanation :

Answer: B) 48 paise Explanation: Quarter of Kg means 250 gm Less weight, less price (Direct Proportion) So, 250 : 200 :: 60 : x => x = 48 So 200 gm will cost 48 paise.

Q: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 1281 1

  • 1
    14 cm
    Correct
    Wrong
  • 2
    13.5 cm
    Correct
    Wrong
  • 3
    12.5 cm
    Correct
    Wrong
  • 4
    11.4 cm
    Correct
    Wrong
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Answer : 3. "12.5 cm"
Explanation :

Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm

Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1838 1

  • 1
    14th element
    Correct
    Wrong
  • 2
    9th element
    Correct
    Wrong
  • 3
    12th element
    Correct
    Wrong
  • 4
    7th element
    Correct
    Wrong
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Answer : 3. "12th element"
Explanation :

Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.

Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3401 0

  • 1
    1080 cm
    Correct
    Wrong
  • 2
    180 m
    Correct
    Wrong
  • 3
    108 m
    Correct
    Wrong
  • 4
    118 cm
    Correct
    Wrong
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Answer : 3. "108 m"
Explanation :

Answer: C) 108 m Explanation: We know the rule that,   At particular time for all object , ratio of height and shadow are same.   Let the height of the pole be 'H'   Then  188=H48   => H = 108 m.

Q: Solve the equation 122x+1 = 1 ? 4078 0

  • 1
    -1/2
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    -1
    Correct
    Wrong
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Answer : 1. "-1/2"
Explanation :

Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120   Leads to 2x + 1 = 0    Solve for x : x = -1/2

Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2407 0

  • 1
    18
    Correct
    Wrong
  • 2
    14
    Correct
    Wrong
  • 3
    22
    Correct
    Wrong
  • 4
    24
    Correct
    Wrong
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Answer : 2. "14"
Explanation :

Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14

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