Aptitude Questions Practice Question and Answer
8Q: 30 рдЖрджрдореА рдХрд┐рд╕реА рдХрд╛рдо рдХреЛ 25 рджрд┐рди рдореЗрдВ рдХрд░ рд╕рдХрддреЗ рд╣реИрдВ рддреЛ рдЙрд╕реА рдХрд╛рдо рдХреЛ 75 рдЖрджрдореА рдХрд┐рддрдиреЗ рджрд┐рди рдореЗрдВ рдХрд░ рдкрд╛рдпреЗрдВрдЧреЗ? 4510 25d1498d097a68b089a7aa7a0
5d1498d097a68b089a7aa7a0- 115false
- 212false
- 316false
- 410true
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Answer : 4. "10"
Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1852 15b5cc73ae4d2b4197774f8bf
5b5cc73ae4d2b4197774f8bf- 114th elementfalse
- 29th elementfalse
- 312th elementtrue
- 47th elementfalse
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Answer : 3. "12th element"
Explanation :
Answer: C) 12th element Explanation: If we consider the third term to be тАШxтАЭThe 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.
Q: 21 рд╡рд╕реНрддреБрдУрдВ рдХрд╛ рдХреНрд░рдп рдореВрд▓реНрдп 15 рд╡рд╕реНрддреБрдУрдВ рдХреЗ рд╡рд┐рдХреНрд░рдп рдореВрд▓реНрдп рдХреЗ рдмрд░рд╛рдмрд░ рд╣реИред рд▓рд╛рдн рдкреНрд░рддрд┐рд╢рдд рд╣реЛрдЧрд╛? 4929 05d132f44925caa2d5bbbff66
5d132f44925caa2d5bbbff66- 125%false
- 230%false
- 333%false
- 440%true
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Answer : 4. "40%"
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3412 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, ┬а At particular time for all object , ratio of height and shadow are same. ┬а Let the height of the pole be 'H' ┬а Then ┬а188=H48 ┬а => H = 108 m.
Q: Solve the equation 122x+1┬а=┬а1┬а? 4081 05b5cc6f4e4d2b4197774efd7
5b5cc6f4e4d2b4197774efd7- 1-1/2true
- 21/2false
- 31false
- 4-1false
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Answer : 1. "-1/2"
Explanation :
Answer: A) -1/2 Explanation: Rewrite equation as┬а122x+1┬а=┬а120 ┬а Leads to 2x + 1 = 0┬а ┬а Solve for x : x = -1/2
Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2424 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
Q: What is the number of digits in┬а333? Given that log3 = 0.47712? 5528 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: ┬аLet ┬а┬аLet┬аx=333┬а=┬а333 ┬а ┬аThen,┬аlogx┬а=┬а33┬аlog3┬а┬а ┬а = 27 x 0.47712 = 12.88224┬а ┬а Since the characteristic in the resultant value of log x is 12 ┬а тИ┤The number of digits in x is (12 + 1) = 13┬а ┬а Hence the required number of digits in┬а333is 13.
Q: рдПрдХ рджреБрдХрд╛рдирджрд╛рд░ рд░реВрдкрдпреЗ рдореЗрдВ 5 рдХреЗ рднрд╛рд╡ рд╕реЗ рдирд╛рд░рдВрдЧреА рдмреЗрдЪрд╛ рдФрд░ рдЙрд╕реЗ 20 рдкреНрд░рддрд┐рд╢рдд рдХрд╛ рд▓рд╛рдн рдкреНрд░рд╛рдкреНрдд рд╣реБрдЖред рд╡рд╣ рд░реВрдкрдпреЗ рдореЗрдВ рдХрд┐рд╕ рднрд╛рд╡ рд╕реЗ рдирд╛рдВрд░рдЧреА рдЦрд░реАрджрд╛ рдерд╛? 3869 05d1338f2d2441c3c5ff90a35
5d1338f2d2441c3c5ff90a35- 13false
- 27false
- 34false
- 46true
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