Directions (41-48): There are 3 bags containing 3 colored balls – Red, Green and Yellow. Bag 1 contains: 24 green balls. Red balls are 4 more than blue balls. Probability of selecting 1 red ball is 4/13. Bag 2 contains: Total balls are 8 more than 7/13 of balls in bag 1. Probability of selecting 1 red ball is 1/3. The ratio of green balls to blue balls is 1: 2 Bag 3 contains: Red balls equal total number of green and blue balls in bag 2. Green balls equal total number of green and red balls in bag 2. Probability of selecting 1 blue ball is 3/14.
Q.41. 1 ball each is chosen from bag 1 and bag 2, What is the probability that 1 is red and other blue?
(A) 15/128
(B) 21/115
(C) 17/135
(D) 25/117
(E) 16/109
Q.42. Some green balls are transferred from bag 1 to bag 3. Now probability of choosing a blue ball from bag 3 becomes 3/16. Find the number of remaining balls in bag 1.
(A) 60
(B) 58
(C) 52
(D) 48
(E) 44
Q.43. Green balls in ratio 4: 1 from bags 1 and 3 respectively are transferred to bag 4. Also 4 and 8 red balls from bags 1 and 3 respectively. Now probability of choosing green ball from bag 4 is 5/11. Find the number of green balls in bag 4?
(A) 12
(B) 15
(C) 10
(D) 9
(E) 11
Q.44. What is the probability that B will speak truth for a particular question asked?
(A) 7/18
(B) 14/33
(C) 4/15
(D) 9/28
(E) 10/33
Q.45. A speaks truth only when B does not speak truth, then what is the probability that C does not speak truth on a question?
(A) 11/140
(B) 21/180
(C) 22/170
(D) 13/140
(E) None of these
Ask me in the comment section, If you face any problem while solving important probability questions.
All the best for the exam!
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