Trigonometry Important Questions for Competitive Exams
$$ Sin^{4}╬╕+Cos^{4}╬╕ $$┬ардХрд╛ рдЕрдзрд┐рдХрддрдо рдорд╛рди рд╣реЛрдЧрд╛?
(A) 2
(B) 3
(C) $$ {1\over2}$$
(D) 1
Correct Answer : D
sec4 A (1 тАУ sin4A) тАУ 2tan2A┬ардХрд╛ рдорд╛рди┬ард╣реИ?
(A) $$ {1\over 2} $$
(B) 0
(C) 2
(D) 1
Correct Answer : D
$$ (x^{b+c})^{b-c}. (x^{c+a})^{c-a}.(x^{a+b})^{a-b}$$ рдХрд╛ рдорд╛рди рд╣реИ рдЬрдм (x тЙа 0)ред
(A) 1
(B) 2
(C) -1
(D) 0
Correct Answer : A
рдпрджрд┐┬а0 тЙд ╬╕ тЙд 900 and 4cos2╬╕ - $$4{\sqrt { 3} \ }cos╬╕$$ + 3 = 0,┬ард╣реИ,┬арддреЛ рдХрд╛ рдорд╛рди┬а╬╕┬ард╣реЛрдЧрд╛?
(A) $$30^0$$
(B) $$90^0$$
(C) $$45^0$$
(D) $$60^0$$
Correct Answer : A
рдпрджрд┐┬а$$ sec ╬╕ ={13 \over 12}$$,┬арддрдерд╛┬а╬╕┬ардиреНрдпреВрдирдХреЛрдг рд╣реИ,┬арддреЛ┬а$$ \sqrt { cot╬╕+tan╬╕} \ $$┬ард╣реИ....
(A) $$ {4 \over 13}$$
(B) $$ {12 \over 2\sqrt{13}}$$
(C) $$ {13 \over 2\sqrt{15}}$$
(D) $$ {2 \over 13}$$
Correct Answer : B
$$ sec{^4}A(1-sin{^4}A)-2tan{^2}A $$┬ардХрд╛ рдорд╛рди рд╣реЛрдЧрд╛:
(A) $$ {1\over2}$$
(B) 0
(C) 2
(D) 1
Correct Answer : D
Explanation :
┬аPut A=45 degree and we can get answer.
рдпрджрд┐ tan2╬╕ +cot2╬╕ ┬а= 2 рддреЛ 2sec╬╕ cosec╬╕ рдХрд╛ рдорд╛рди рдХреНрдпрд╛ рд╣реИ?
(A) 0
(B) 1
(C) 2
(D) 4
Correct Answer : D
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Vikram Singh
Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.
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