Trigonometry Practice Question and Answer
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Q: $$ {(sec^{2}θ+tanθ\cotθ-tan^{2}θ)}$$ का मान होगा।
945 05feeea721f464d740159faae
5feeea721f464d740159faae- 11false
- 22true
- 30false
- 44false
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Answer : 2. "2"
Q: $$ \sqrt{(1-sin^{2}θ) ÷(1-cos^{2}θ)}$$ सरल कीजिए।
941 05feeea39d6478d50161e794d
5feeea39d6478d50161e794d- 1Cot θtrue
- 2Tan θfalse
- 3Sec θfalse
- 4Cosec θfalse
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Answer : 1. "Cot θ"
Q: यदि tan (11 θ)=cot (7θ), है तो sin2(6 θ) + Sec2 (9 θ) + cosec2(12 θ) का मान क्या होगा?
1284 05fc0e22d96415e6951a99e17
5fc0e22d96415e6951a99e17- 1$$ {23\over 6}$$false
- 2$$ {35\over 12}$$false
- 3$$ {31\over 12}$$false
- 4$$ {43\over 12}$$true
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Answer : 4. "$$ {43\over 12}$$"
Q: यदि 3 + cos2θ= 3(cot2θ + Sin2θ), 0°<θ<90°, है तो (cosθ +2sinθ) का मान क्या होगा?
868 05fbf73c64f2f6c622be747fa
5fbf73c64f2f6c622be747fa- 1$$ {2\sqrt{3}+1\over {2}}$$true
- 2$$ {3\sqrt{2}}$$false
- 3$$ {3\sqrt{3}+1\over {2}}$$false
- 4$$ {\sqrt{3}+2\over 2}$$false
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Answer : 1. "$$ {2\sqrt{3}+1\over {2}}$$"
Q: यदि $$ {\sqrt{3}\ CosA=SinA}$$ है तो Cot A का मान ज्ञात कीजिए
1030 05f97fe1ced7fc21d78dd070e
5f97fe1ced7fc21d78dd070e- 1$$ {\sqrt{3}}$$false
- 2$$ {2\over {\sqrt{3}}}$$false
- 3$$ {1\over {\sqrt{3}}}$$true
- 42false
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Answer : 3. "$$ {1\over {\sqrt{3}}}$$"
Q: यदि $$ {sin\ θ\ cosec\ θ\over tan θ}=4 $$ है तो tan θ का मान ज्ञात किजिए।
908 05f97fdabd433054b5c8aecd5
5f97fdabd433054b5c8aecd5- 14false
- 2$$ {1\over 4}$$true
- 33false
- 45false
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Answer : 2. "$$ {1\over 4}$$"
Q: दिए गए समीकरण को हल कीजिए।
$$ {{cot \ 30°}\over {1+sin\ 45°}}+{{1+sin\ 45°}\over cot \ 30°}=?$$
2259 05f96bdd6d8201a50c263815f
5f96bdd6d8201a50c263815f- 1$$ {5\sqrt{3}}-{6\sqrt{6}}\over 6$$false
- 2$$ {3-2\sqrt{3}}$$false
- 3$$ {14\sqrt{3}}-{5\sqrt{6}}\over 6$$true
- 4$$ {6\sqrt{6}}-{5\sqrt{3}}\over 6$$false
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Answer : 3. "$$ {14\sqrt{3}}-{5\sqrt{6}}\over 6$$"
Q: $$ {\sqrt{(cos^{2}20°+cos^{2}70°)}}$$ का मान ज्ञात कीजिये।
980 05f881866f28f4b47be27e642
5f881866f28f4b47be27e642- 10false
- 2$$ {2\over{\sqrt{3}}}$$false
- 31true
- 4$$ {\sqrt{3}\over2}$$false
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Answer : 3. "1"
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