Boat and Stream Practice Question and Answer

Q:

рдПрдХ рдирд╛рд╡рд┐рдХ рдирджреА рдХреА рдзрд╛рд░рд╛ рдХреЗ рд╡рд┐рд░реБрджреНрдз┬а5┬ардШрдВрдЯреЗ рдореЗрдВ┬а12┬ардХрд┐.рдореА. рдХреА рджреВрд░реА рддрдп рдХрд░рддрд╛ рд╣реИ ред рдЙрд╕реА рд╕рдордп рдореЗрдВ рдзрд╛рд░рд╛ рдХреА рджрд┐рд╢рд╛ рдореЗрдВ┬а22 ┬ардХрд┐.рдореА. рдХреА рджреВрд░реА рддрдп рдХрд░рддрд╛ рд╣реИ ред рддреЛ рдзрд╛рд░рд╛ рдХрд╛ рд╡реЗрдЧ рд╣реИ┬а|┬а

2045 0

  • 1
    1 рдХрд┐.рдореА рдкреНрд░рддрд┐ рдШрдВрдЯрд╛
    Correct
    Wrong
  • 2
    2 рдХрд┐.рдореА рдкреНрд░рддрд┐ рдШрдВрдЯрд╛
    Correct
    Wrong
  • 3
    1.5 рдХрд┐.рдореА рдкреНрд░рддрд┐ рдШрдВрдЯрд╛
    Correct
    Wrong
  • 4
    2.5 рдХрд┐.рдореА рдкреНрд░рддрд┐ рдШрдЯрд╛
    Correct
    Wrong
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Answer : 1. "1 рдХрд┐.рдореА рдкреНрд░рддрд┐ рдШрдВрдЯрд╛ "

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Answer : 3. "10"

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Answer : 4. "8:3"
Explanation :

Answer: D) 8:3 Explanation: Let the speed of the boat upstream be p┬аkmph┬аand that of downstream be q┬аkmph ┬а Time for upstream = 8 hrs 48 min =┬а845hrs ┬а Time for downstream = 4 hrs ┬а Distance in both the cases is same. ┬а => p x┬а┬а845= q x 4 ┬а => 44p/5 = 4q ┬а => q = 11p/5 ┬а ┬аNow, the required ratio of Speed of boat : Speed of water current ┬а =┬аq+p2:q-p2 ┬а => (11p/5 + p)/2┬а : (11p/5 - p)/2 ┬а => 8 : 3

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