Calendar Aptitude Questions Practice Question and Answer
2 4 Q:
5df9ee6e8014020c092ecac9 4 Answer : 3. "Wednesday"
Q: यदि माह के तीसरे शुक्र को 16 तारीख है, तो उसी माह के चौथे मंगलवार को क्या तारीख होगी ?
4021 05df9ee6e8014020c092ecac9
5df9ee6e8014020c092ecac9- 120thfalse
- 222ndfalse
- 327thtrue
- 429thfalse
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Answer : 3. "27th "
Q: What was the day of the week on 17th June, 1998 ? 4998 75b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
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Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
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