प्रतियोगी परीक्षाओं के लिए सरलीकरण प्रश्न और उत्तर
$$ {4\over 5}×[{1\over 2}\ of\ 25]+12÷{3\over 4}-32=?$$
(A) 8
(B) –2
(C) –6
(D) 12
Correct Answer : C
$$ {\sqrt{0.6912}+{\sqrt{0.5292}}\over {\sqrt{0.6912}-{\sqrt{0.5292}}}}$$ का मान होगा—
(A) 15
(B) 1.5
(C) 0.9
(D) 9
Correct Answer : A
$${0.74×1.23×0.13\over (0.37)^{3}+(0.41)^{3}-8(0.39)^{3}}$$ का मान क्या होगा?
(A) 1
(B) $$ {-1\over 3}$$
(C) $$ {1\over 3}$$
(D) -1
Correct Answer : B
$$ {5-[2+3(2-2× 2 +5)-5]÷5}\over {4×4÷4}of(4+4÷4 of 4)$$ का मान होगा—
(A) $$ {3}{3\over 16}$$
(B) $$ {4}{3\over 80}$$
(C) $$ {2\over 5}$$
(D) $$ {7}{3\over 5}$$
Correct Answer : B
दिए गए समीकरण का मान ज्ञात करों?
$$\left({216\over1} \right) ^{-{2\over3}}÷\left({27\over1} \right) ^{-{4\over3}}=? $$
(A) $$ {4\over9}$$
(B) $$ {9\over4}$$
(C) $$ {9\over5}$$
(D) $$ {3\over5}$$
Correct Answer : B
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enhttps://www.hindi.examsbook.com/simplification-questions-and-answer/666simplification-questions-and-answerAbout author
Gajanand
B-Tech Electronic and Communication Engineering select the SSC CGL Tier-1 and Tier-2 in 2016 and Rajasthan state Govt. Exams Expert in Mathematics , Reasoning Gk and English.
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