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(1+sinα) (1-sinβ) (1+sinγ)= (1-sinα) (1-sinβ) (1-sinγ)=?
5Q:
(1+sinα) (1-sinβ) (1+sinγ)= (1-sinα) (1-sinβ) (1-sinγ)=?
- 1±cosαcosβcosγtrue
- 2±sinαsinβsinγfalse
- 3±sinαcosβsecγfalse
- 4±sinαsinβcosγfalse
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