जॉइन Examsbookउत्तर : 4. "1022"
Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ?5
प्र: Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ?
- 11020false
- 21040false
- 31060false
- 41022true
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उत्तर : 4. "1022"
व्याख्या :
Answer: D) 1022 Explanation: Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.Now, add the remainder 2 that's required. Thus, the answer is 1022.