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प्र: In the series given below , how many 8's are there each of which is exactly divisible by its immediate preceeding as well as succeeding numbers ?2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 2140 0

  • 1
    five
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  • 2
    four
    सही
    गलत
  • 3
    two
    सही
    गलत
  • 4
    one
    सही
    गलत
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उत्तर : 3. "two"
व्याख्या :

Answer: C) two Explanation: Clearly, we may mark such sets of 3 numbers, in which the middle number is 8 and each of the two numbers on both sides of it is a factor of 8, as shown below : 2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 So, there are two such 8's. Hence the answer is C.

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उत्तर :
व्याख्या :

1. Answer (c) Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it. Required number of apples = number of 1's - number of 4's = 6 - 4 = 2 2. Answer (d) Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it. Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's) = 6 + 6 + 7 - (2x4) = 19 - 8 = 11.

प्र: Statement: There was a spurt in criminal activities in the city during the recent festival season.Courses of action:a. The police should immediately investigate into the causes of this increase.b. In future the police should take adequate precaution to avoid recurrence of such situation during festival.c. The known criminals should be arrested before any such season. 1473 0

  • 1
    Both a and b follows
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  • 2
    Only c follows
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  • 3
    Only a follows
    सही
    गलत
  • 4
    Both b and c follows
    सही
    गलत
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उत्तर : 1. "Both a and b follows"
व्याख्या :

Answer: A) Both a and b follows Explanation: The police ought to find out the lackenings in existing security arrangements and make up for these inadequacies to strengthen security and thus prevent criminal activities in the forthcoming festival. So, both a and b follow. Arresting the known criminals does not ensure safety, for a novice can also indulge in crime. So, c does not follow.

प्र: A polygon has 44 diagonals, then the number of its sides are ? 1181 0

  • 1
    13
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  • 2
    9
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  • 3
    11
    सही
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  • 4
    7
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उत्तर : 3. "11"
व्याख्या :

Answer: C) 11 Explanation: Let the number of sides be n.  The number of diagonals is given by nC2 - n   Therefore, nC2 - n = 44, n>0  nC2 - n = 44 n2 - 3n - 88 = 0  n2 -11n + 8n - 88 = 0   n(n - 11) + 8(n - 11) = 0  n = -8 or n = 11.   As n>0, n will not be -8. Therefore, n=11.

प्र: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 2607 0

  • 1
    215
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  • 2
    315
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  • 3
    415
    सही
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  • 4
    115
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उत्तर : 2. "315"
व्याख्या :

Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect.   Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines.   Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315

प्र: There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ? 3936 0

  • 1
    105
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  • 2
    7! x 6!
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  • 3
    7!/5!
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  • 4
    420
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उत्तर : 1. "105"
व्याख्या :

Answer: A) 105 Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,   Then, 7C1 x 6C2 x 4C4  = 7 x 15 x 1 = 105

प्र: The value of -4-(-10) is how much greater then the value of -10-(-4) ? 1967 0

  • 1
    10
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  • 2
    6
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  • 3
    12
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  • 4
    0
    सही
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उत्तर : 3. "12"
व्याख्या :

Answer: C) 12 Explanation: -4-(-10) = -4+10 = 6   -10-(-4) = -10+4= -6   Therefore, 6-(-6) = 6+6 = 12

प्र: Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + .... 1264 0

  • 1
    30,400
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  • 2
    30,200
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  • 3
    34,600
    सही
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  • 4
    38,400
    सही
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उत्तर : 1. "30,400"
व्याख्या :

Answer: A) 30,400 Explanation: we can treat every two consecutive terms as one.So, we will have a total of 100 terms of the nature:(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,....   We know the sum of n terms  nn+12   Now, a= 7, d=6 and n=100Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6]=> 50[608]=> 30,400.

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