Answer: B) 34 yrs Explanation: Total age of players in team = 22 x 11 = 242When coach is included, total members = 12, Avg age increases by one becomes 23Total age when coach is included = 23x12 = 276Age of coach = 276-242 = 34 yrs.

Answer: D) 70 kmph Explanation: By car 240 km at 60 kmphTime taken = 240/60 = 4 hr. By train 240 km at 60 kmphTime taken = 400/100 = 4 hr. By bus 240 km at 60 kmphTime taken = 200/50 = 4 hr. So total time = 4 + 4 + 4 = 12 hr. and total speed = 240+400+200 = 840 kmAverage speed of the whole journey = 840/12 = 70 kmph.

Answer: C) 32 Explanation: Probability of left handed = 4/5total student = 40total left handed = 40 x(4/5)= 32

Answer: B) 4 % Explanation: Imension of the duster is assumed as 5x5x7 cm3 Volume of the duster below the water layer= volume of water increased= πxrxrxh = 3.14×52×2.14 ≈ 168 cm3 Total volume of the duster = 5×5×7 = 175 cm3 Percentage of the duster part below the layer = 168×100/175 = 96% Percentage of the duster part above the layer = 4%

Answer: D) 0 Explanation: As we know we have 10 letter and 10 different address and one more information given that exactly 9 letter will at the correct address....so the remaining one letter automatically reach to their correct address P(E) = favorable outcomes /total outcomesHere favorable outcomes are '0'.So probability is '0'.

Answer: B) 17 Explanation: Total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from topand ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.Hence num of boys below radhika are 26-9=17

Answer: A) 64 Explanation: Volume of cuboid = (24 x 9 x 8) cm = 1728 cu.cmVolume of small cube = (3 x 3 x 3) cm = 27 cu.cm So, No. of small cubes formed = 1728/27 = 64.

Answer: B) 147320 Explanation: Sum of 4 digit numbers = (2+4+6+8) x P33 x (1111) = 20 x 6 x 1111 = 133320  Sum of 3 digit numbers = (2+4+6+8) x P23 x (111) = 20 x 6 x 111 = 13320  Sum of 2 digit numbers = (2+4+6+8) x P13 x (11) = 20 x 3 x 11 = 660  Sum of 1 digit numbers = (2+4+6+8) x P03 x (1) = 20 x 1 x 1 = 20    Adding All , Sum = 147320