Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain ? 1671 0

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    25%
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  • 2
    30%
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    17%
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  • 4
    19%
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उत्तर : 1. "25%"
व्याख्या :

Answer: A) 25% Explanation: He has gain = 15 - 12 = 3,Gain% = (3/12) x 100 = (100/4) = 25.He has 25% gain.

प्र: What is the smallest number by which 2880 must be divided in order to make it into a perfect square ? 1554 0

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    2
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    3
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    4
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    5
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उत्तर : 4. "5"
व्याख्या :

Answer: D) 5 Explanation: By trial and error method, we get2880/3 = 960 is not a perfect square2880/4 = 720 is not a perfect square2880/5 = 576 which is perfect square of 24Hence, 5 is the least number by which 2880 must be divided in order to make it into a perfect square.

प्र: (3x + 2) (2x - 5) = ax² + kx + n. What is the value of  a - n + k ? 1681 0

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    4
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    1
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    5
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    3
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उत्तर : 3. "5"
व्याख्या :

Answer: C) 5 Explanation: (3x + 2) (2x - 5) = ax2+kx+n ...............(1)   But (3x + 2)(2x - 5) = 6x2-11x-10........(2)   so by comparing (1) & (2),   we get a= 6, k= -11 , n= -10   (a - n + k) = 6 + 10 - 11 = 5.

प्र: In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ? 1369 0

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    25 m
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    21 m
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    22 m
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    19 m
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उत्तर : 1. "25 m"
व्याख्या :

Answer: A) 25 m Explanation: A:B = 200 : 169A:C = 200 : 182 CB = CA×AB    182200×200169   => 182:169   When C covers 182 m , B Covers 169 mWhen C covers 350 m , B Covers 169182×350=> 325 m       So C beats B by (350 - 325) = 25 m.

प्र: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 3894 0

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    1124
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    1420
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    1345
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    1250
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उत्तर : 4. "1250"
व्याख्या :

Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

प्र: 'K' cycled from A to B at 10 kmph and returned at the rate of 9 kmph. 'L' cycled both ways at 12 kmph. In the whole journey 'L' took 10 minutes less than 'K'. Find the distance between A and B ? 1351 0

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    32.1 km
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    15.23 km
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    3.75 km
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    32.1 m
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उत्तर : 3. "3.75 km"
व्याख्या :

Answer: C) 3.75 km Explanation: Let 'd' be the distance between A and BK -time = d/10 + d/9 = 19d/90 hoursL -time = 2d/12 = d/6 hoursWe know that, 10 min = 1/6 hoursThus, time difference between K and L is given as 10 minutes. => 19d/90 - d/6 = 1/6=> (19d-15d)/90 = 1/6=> 4d/90 = 1/6Thus,d= 15/4 km = 3.75 km. hence the distance between A and B is 3.75 km.

प्र: The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is ? 2469 0

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    6 ml
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    11 ml
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    15 ml
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    9 ml
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उत्तर : 1. "6 ml"
व्याख्या :

Answer: A) 6 ml Explanation: Let us assume that the lotion has 50% alcohol and 50% water.ratio = 1:1As the total solution is 9mlalcohol = water = 4.5mlNow if we want the quantity of alcohol = 30%The quantity of water = 70%The new ratio = 3:7Let x ml of water be addedWe get,4.54.5+x = 37=> x=6Hence 6ml of water is added.

प्र: Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ? 1456 0

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    24 km
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    50 km
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    42 km
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    30 km
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उत्तर : 2. "50 km"
व्याख्या :

Answer: B) 50 km Explanation: We know 60 min = 1 hrTotal northward Laxmi's distance = 20kmph x 1hr = 20 kmTotal southward Prasanna's distance = 30kmph x 1hr = 30 kmTotal distance between Prasanna and Laxmi is = 20 + 30 = 50 km.

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