Quantitative Aptitude рдкреНрд░рд╢реНрди рдФрд░ рдЙрддреНрддрд░ рдХрд╛ рдЕрднреНрдпрд╛рд╕ рдХрд░реЗрдВ

рдкреНрд░: A six-digit number is formed by repeating a three-digit number; for example, 404404 or 415415 etc. Any number of this form is always exactly divisible by 1417 0

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    101
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    901
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    1001
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    789
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рдЙрддреНрддрд░ : 3. "1001"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 1001 Explanation: Here by trial and error method, we can obseve that 404404 = 404 x 1001; 415415 = 415 x 1001, etc. So, any number of this form is divisible by 1001.

рдкреНрд░: A teacher multiplies 987 by a certain number and obtains 556781 as her answer. If in the answer, both 6 and 7 are wrong but the other digits are correct, then the correct answer will be 1364 0

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    553681
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    555181
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    556581
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    555681
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рдЙрддреНрддрд░ : 4. "555681"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) 555681 Explanation: Given number is 987 = 3 x 7 x 47. So, required number must be divisible by each one of 3, 7, 47. None of the numbers in 553681 and 555181 are divisible by 3. While 556581 is not divisible by 7.Correct answer is 555681.

рдкреНрд░: AvanthiтАЩs age is 1/6th of her fatherтАЩs age. Her fatherтАЩs age will be twice of KapilтАЩs age after 10 years. If KapilтАЩs eighth birthday was celebrated two years ago, then what is AvanthiтАЩs present age ? 1510 0

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    6 years
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    4 years
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    7 years
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    None
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рдЙрддреНрддрд░ : 4. "None"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: D) None Explanation: As given Kapil's 8th birthday was celebrated 2 years ago, KapilтАЩs present age = 8 + 2 = 10 years. Father's age is twice of KapilтАЩs age after 10 years. => F + 10 = 2 (K + 10) = 2 (10+ 10)F = 30years, Avanthi's age =1/6(F) = 30/6 = 5 years.

рдкреНрд░: The difference between two numbers is 3355. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number and larger number respectively ? 1308 0

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    546, 3901
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    415, 3770
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    668, 4023
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    404, 3759
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рдЙрддреНрддрд░ : 3. "668, 4023"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: C) 668, 4023 Explanation: Let the smaller number be k.Then, larger number = (3355 + k)Therefore 3355 + k = (6k + 15)тА╣=тА║ 5k = 3340тА╣=тА║ k = 668. Therefore, the smaller number k = 668 and now the larger number = 3355+668 = 4023.

рдкреНрд░: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1169 0

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    15 days
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    13 days
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    12 days
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    10 days
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рдЙрддреНрддрд░ : 1. "15 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10   Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5   1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.

рдкреНрд░: The ratio between the number of sheep and the number of horses at the Stewar farm is 4 to 15. If each of horse is fed 110 ounces of horse food per day and the farm needs a total 13200 ounces of horse food per day. what is number sheep in the form ? 1309 0

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    32
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    36
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    44
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    52
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рдЙрддреНрддрд░ : 1. "32"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 32 Explanation: Given ratio of number of sheep and horses = 4 : 15Let number of sheep and horses are 4k and 15k Number of horses = 13200/110 = 120 Now 15K = 120 and k = 8 Number of sheep = 4k = (4 x 8) = 32

рдкреНрд░: Raghu earns 25% on an investment but loses 10% on another investment. If the ratio of the two investment is 3:5. What is the gain or loss on two investments taken together ? 1499 0

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    1.251 %
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    3.125 %
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    7.21 %
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    9.451 %
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рдЙрддреНрддрд░ : 2. "3.125 %"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: B) 3.125 % Explanation: Taking the 2 investments to be 3x and 5x respectivelyTotal income of Raghu = (3x) x 1.25 + (5x) x 0.9 = 8.25Therefore, Gain% = 0.25/8 x 100 = 3.125 %.

рдкреНрд░: A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together? 2232 0

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    12 days
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    24 days
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    32 days
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    16 days
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рдЙрддреНрддрд░ : 1. "12 days"
рд╡реНрдпрд╛рдЦреНрдпрд╛ :

Answer: A) 12 days Explanation: It is given that efficiency ratio =3:1 so time ratio will be 1:3 (since work is same)   Also given that time diff = 32 days. ratio difference = 3-1 =2  2 ratio = 32 days 1 ratio = 16 days. So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.   Total work = LCM of 16 and 48 = 48. Total time = Total work/Total efficiency  ie; 48/4= 12 days.

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ

  рддреНрд░реБрдЯрд┐ рдХреА рд░рд┐рдкреЛрд░реНрдЯ рдХрд░реЗрдВ

рдХреГрдкрдпрд╛ рд╕рдВрджреЗрд╢ рджрд░реНрдЬ рдХрд░реЗрдВ
рддреНрд░реБрдЯрд┐ рд░рд┐рдкреЛрд░реНрдЯ рд╕рдлрд▓рддрд╛рдкреВрд░реНрд╡рдХ рдЬрдорд╛ рд╣реБрдИ