Quantitative Aptitude प्रश्न और उत्तर का अभ्यास करें

प्र: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1251 0

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    Only a is sufficient
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  • 2
    Neither a nor b is sufficient
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  • 3
    Only b is sufficient
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  • 4
    Both a and b sufficient
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उत्तर : 4. "Both a and b sufficient"
व्याख्या :

Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.

प्र: There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ? 1769 0

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    Rs. 5422
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  • 2
    Rs. 5489
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  • 3
    Rs. 3972
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  • 4
    Rs. 6145
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उत्तर : 3. "Rs. 3972"
व्याख्या :

Answer: C) Rs. 3972 Explanation: Let p = Rs. 100. Then, S.I is Rs. 50 and time = 5 years.  ∴ R = 100×50100×5= 10% p.a.   Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a. C.I. = Rs. 12000×1+101003-1= Rs. 3972

प्र: The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ? 1323 1

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    Rs. 1100
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    Rs. 5500
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    Rs. 1400
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  • 4
    Rs. 4120
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उत्तर : 1. "Rs. 1100"
व्याख्या :

Answer: A) Rs. 1100 Explanation: Let the sum be Rs.x. Then,     x1+101002-x=1155   ⇒x11102-1=1155   => x =5500   sum = Rs. 5500.   So, S.I = Rs. 5500×5×4100 = 1100

प्र: Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank? 6032 0

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    48min
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  • 2
    72min
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    24min
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    None of these
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उत्तर : 3. "24min"
व्याख्या :

Answer: C) 24min Explanation: Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore,   part filled by tap X in 1 minute = 1/30   part filled by tap Y in 1 minute = 1/40   Tap Z can empty the tank in 60 minutes. Therefore,   part emptied by tap Z in 1 minute = 1/60   Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24   i.e., the tank can be filled in 24 minutes.

प्र: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1567 0

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    12 a.m.
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    1 p.m.
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    11 a.m.
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  • 4
    12 p.m.
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उत्तर : 4. "12 p.m."
व्याख्या :

Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.

प्र: A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ? 1140 0

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    48 kmph
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  • 2
    50 kmph
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  • 3
    46 kmph
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  • 4
    42 kmph
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उत्तर : 1. "48 kmph"
व्याख्या :

Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken.   i.e. 2xx60+x40   => 2x5x120   = 48 kmph.

प्र: A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? 1226 0

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    107 kmph
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    106 kmph
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    72 kmph
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    76 kmph
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उत्तर : 2. "106 kmph"
व्याख्या :

Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.

प्र: A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph. 1931 0

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    4314
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  • 2
    4213
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    2413
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  • 4
    3414
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उत्तर : 2. "4213"
व्याख्या :

Answer: B) Option B Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmphtime taken indivisually: => 6/1.5 = 4 m=> 8/2 = 4 m=> 40/8 = 5 m   Average speed of man= total distance/ total time=> 54/13 = 4213 kmph

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