Quantitative Aptitude Practice Question and Answer
8Q: A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel? 13346 15b5cc77fe4d2b41977750183
5b5cc77fe4d2b41977750183- 11100false
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Answer : 3. "1400"
Explanation :
Answer: C) 1400 Explanation: Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15 Distance covered by both the wheels is the same 40*(n+3)=70n n=20 Front wheel : Back Wheel Circumference 40 : 70 Revolutions 35 : 20 Distance covered : 40×35 = 70×20 = 1400 inches.
Q: In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ? 4368 05b5cc77fe4d2b4197775017e
5b5cc77fe4d2b4197775017e- 126true
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Answer : 1. "26"
Explanation :
Answer: A) 26 Explanation: Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600 Find a number which exactly divide all these numbers That is HCF of 18000, 9600& 3600 All the value has 00 at end so the factor will also have 00. HCF for 180, 96 & 36. Factors of 180 = 3 x 3 x 5 x 2 x 2 96 = 2 x 2 x 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 Common factors are 2x2×3=12 Therefore, Actual HCF is 1200 Gold Coins 18000/1200 will be in 15 rooms Silver Coins 9600/1200 will be in 8 rooms Bronze Coins 3600/1200 will be in 3 rooms Total rooms will be (15+8+3) = 26 rooms.
Q: Find the unit digit of 4198 + 612345 + 34866 + 2411 + 1. 5113 05b5cc77fe4d2b41977750179
5b5cc77fe4d2b41977750179- 13false
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Answer : 3. "1"
Explanation :
Answer: C) 1 Explanation: Given that, 4198+612345+34866+2411+1 Now Power Cycle of 4 is 4, 6 6 is 6 8 is 8, 4, 2, 6 1 is 1 4198- 198 is even number , So the unit digit value is 6 612345 - It is always 6 34866- 66/4 the remainder is 2 , So the second value is 4 2411- 11 is odd number, So the unit digit value is 4 1 - It is always 1 Total = 21 Therefore, The unit digit is 1
Q: The minimum number of half years in which a sum of money kept at 60% compound interest will be quadrupled is ? 2212 05b5cc77fe4d2b4197775016f
5b5cc77fe4d2b4197775016f- 12false
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Answer : 4. "6"
Explanation :
Answer: D) 6 Explanation: Let us assume Amount be 100 Rs and we calculate in CI First year 60% of 100 = 60 amount (100+60) is 160 Second year 60% of 160 = 96 amount (160+96) is 256 Third year 60% of 256 =153.6 amount (256+153.6) is 409.6 Here the Amount of 100 Rs is quadrapled in 3 years. One year contains 2 half years Three year has 6 half years. Therefore, It takes 6 half years.
Q: If the cost price of a certain object doubles, then the loss gets tripled of what it was initially. The initial loss % was ? 11479 05b5cc77fe4d2b41977750174
5b5cc77fe4d2b41977750174- 10 %false
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Answer : 4. "50 %"
Explanation :
Answer: D) 50 % Explanation: Let the cost price be x and selling price be y.Loss = x – y When the cost price doubles, the loss gets tripled.So it becomes like this, 2x – y = 3(x-y) => x = 2y Loss % = (loss/ C.P) x 100 = [(2y-y)/2y] x 100= 50 %
Q: Two bike riders ride in opposite directions around a circular track, starting at the same time from the same point. Biker A rides at a speed of 16 kmph and biker B rides at a speed of 14 kmph. If the track has a diameter of 40 km, after how much time (in hours) will the two bikers meet? 10105 15b5cc77fe4d2b4197775016a
5b5cc77fe4d2b4197775016a- 16.52false
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- 34.18true
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Answer : 3. "4.18"
Explanation :
Answer: C) 4.18 Explanation: Distance to be covered = πD = 40π km Relative speed of bikers = 16 + 14 = 30 kmph. Now, time=distancespeed = 40π30 = 4.18 hrs.
Q: From a bunch of flowers having 16 red roses and 14 white roses, four flowers have to be selected. In how many different ways can they be selected such that at least one red rose is selected? 1851 05b5cc77ae4d2b41977750165
5b5cc77ae4d2b41977750165- 127405false
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Answer : 4. "27404"
Explanation :
Answer: D) 27404 Explanation: Given total 16 Red roses and 14 White roses = 30 roses Four flowers have to be selected from 30 i.e, C430= 27405 Ways Now, atleast one Red rose is selected i.e, 27405(total) - 1(all four are white roses) = 27404 ways.
Q: If log 64 = 1.8061, then the value of log 16 will be (approx)? 4299 05b5cc77ae4d2b41977750160
5b5cc77ae4d2b41977750160- 11.9048false
- 21.2040true
- 30.9840false
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Answer : 2. "1.2040"
Explanation :
Answer: B) 1.2040 Explanation: Given that, log 64 = 1.8061 i.e log43=1.8061 --> 3 log 4 = 1.8061 --> log 4 = 0.6020 --> 2 log 4 = 1.2040 ⇒log42=1.2040 Therefore, log 16 = 1.2040