Answer: C) The Himalayas provide the barrier effect Explanation: The whole of India, south of the Himalayas can be climatically treated as a tropical country as the Himalayas provide the barrier effect.    Indian subcontinent is separated from the rest of Asia by the lofty Himalayan ranges which block the cold air masses moving southwards from Central Asia.     As a result, during winters, the northern half of India is warmer by 3°C to 8°C than other areas located on same latitudes.    During summer, due to over the head position of the sun, the climate in the southern parts resemble equatorial dry climate.   The seasonal reversal of winds in Arabian Sea and Bay of Bengal give India a typical tropical monsoon climate.   So Indian climate, to be precise, is Tropical monsoon type (a distinct wet and dry climate) rather than just a tropical or half temperate climate.

Answer: D) U Explanation: If all the A's are dropped from the above arrangement, we get   C U B E D E D B E B U C D B C D B D U B C C B E D.    Here the eleventh from the left end of the above arrangement is U

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd.   4 women can be arranged at 4 even places in 4! ways.   and 5 men can be placed in remaining 5 places in 5! ways.   Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

Answer: B) 360 Explanation: There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times.    Number of 7 digit numbers = 7!3!×2! = 420   But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. The number of such numbers beginning with '0'.   =6!3!×2! = 60   Hence the required number of 7 digits numbers = 420 - 60 = 360

Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking.    (i) 1 lady out of 4 and 4 gentlemen out of 6  (ii) 2 ladies out of 4 and 3 gentlemen out of 6  (iii) 3 ladies out of 4 and 2 gentlemen out of 6  (iv) 4 ladies out of 4 and 1 gentlemen out of 6    In case I the number of ways = C14×C46 = 4 x 15 = 60  In case II the number of ways = C24×C36 = 6 x 20 = 120  In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6    Hence, the required number of ways = 60 + 120 + 60 + 6 = 246

Answer: B) 2 x (18!) Explanation: A person can be chosen out of 18 people in 18 ways to be seated between Musharraf and Manmohan. Now consider Musharraf, Manmohan, and the third person, sitting between them, as a single personality, we can arrange them in 17! ways but Musharraf and Manmohan can also be arranged in 2 ways.    Required number of permutations = 18 x (17!) x 2 = 2 x 18!

Answer: B) 535 Explanation: The number of points of intersection of 37 lines is C237. But 13 straight lines out of the given 37 straight lines pass through the same point A.   Therefore instead of getting C213 points, we get only one point A. Similarly 11 straight lines out of the given 37 straight lines intersect at point B. Therefore instead of getting C211 points, we get only one point B.    Hence the number of intersection points of the lines is C237-C213-C211 +2 = 535

Answer: C) 3/4 Explanation: Let A, B, C be the respective events of solving the problem and A , B, C be the respective events of not solving the problem. Then A, B, C are independent event ∴A, B, C are independent events Now,  P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4  PA=12, PB=23, PC= 34 ∴ P( none  solves the problem) = P(not A) and (not B) and (not C)                     = PA∩B∩C                    = PAPBPC         ∵ A, B, C are Independent                                          =  12×23×34                     = 14   Hence, P(the problem will be solved) = 1 - P(none solves the problem)                  = 1-14= 3/4