Answer: C) 1/221 Explanation: Total Combination of getting a card from 52 cards = C152 Because there is no replacement, so number of cards after getting first card= 51 Now, Combination of getting an another card= C151 Total combination of getting 2 cards from 52 cards without replacement= (C152×C151)  There are total 4 Ace in stack. Combination of getting 1 Ace is = C14   Because there is no replacement, So number of cards after getting first Ace = 3 Combination of getting an another Ace = C13 Total Combination of getting 2 Ace without replacement=C14×C13 Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.

Answer: C) 16/25 Explanation: If there are total 100 candidates, 40 candidates are really capable and 60 candidates are incapable.Of the candidates who are really capable = 80% 40*(80/100)=32 pass the test andof the incapable= 30%60*(30/100)=18 pass the test.Total candidates who passed the test = 32+18 = 50The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

Answer: C) T Explanation: 1ST SERIES = M J G... It decreasing by 3 alphabets.2ND SERIES = N Q... It increasing by 3 alphabets. M N J Q G T...

Answer: A) 14.28 % profit Explanation: Let 1kg of Rs. 100 then 840gm is of Rs. 84.Now (label on can 1kg but contains 840kg ) so for customer it is of Rs. 100 and further gives 4% discount [he sells his article on 4% loss on cost price.] So now S.P = Rs. 96But actually it contains 840 gm so C.P for shopkeeper = Rs. 84S.P = Rs. 96C.P = Rs. 84Profit% = {(S.P-C.P)/C.P}x100{(96-84)/84} x 100 = 14.28571429% PROFIT.

Answer: B) 10 Explanation: Raj Tarun's age = 0 when he was born.Then, given his brother is 6 years old.Then his father is 6 + 32 = 38 when Raj Tarun was bornAnd his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was bornand his sister is 25 year younger than his mother so Raj Tarun's sister was 10 years old when Raj Tarun was born.

Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

Answer: A) 140 kms Explanation: It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, theDistance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 kmSo train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutesSo distance from A = Distance traveled by 2nd train in 3 hr. 30 min = 40 x 3.5 = 140 km.

Answer: D) 2, 3, 1, 5, 4 Explanation: Firstly Rain falls and then Sun comes and Rainbow forms. After that Child sees the rainbow and feels Happy.