IIT JEE Practice Question and Answer
8Q: In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20 seconds. What is the speed of Piyush and Kaushik respectively ? If the ratio of respective speeds be 3:2. 2118 05b5cc7d0e4d2b419777511f4
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Answer :
Explanation :
Let the speed of Kaushik be Sk and speed of Piyush be Sp and let the time taken by Piyush be t second then, SkSp = 800t+20600t = 23since given ratio t = 20 s Speed of Piyush = Sp = 600/20 = 30 m/s and Speed of Kaushik = 800/40 = 20 m/s
Q: A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course: 4110 05b5cc7d0e4d2b419777511e0
5b5cc7d0e4d2b419777511e0- 18 minfalse
- 27.5 mintrue
- 312.5 minfalse
- 412 minfalse
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Answer : 2. "7.5 min"
Explanation :
Answer: B) 7.5 min Explanation: B runs around the track in 10 min. i.e , Speed of B = 10 min per round Therefore, A beats B by 1 round Time taken by A to complete 4 rounds = Time taken by B to complete 3 rounds = 30 min Therefore, A's speed = 30/4 min per round = 7.5 min per round Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Q: Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together? 3836 05b5cc7d0e4d2b419777511db
5b5cc7d0e4d2b419777511db- 16false
- 28true
- 39false
- 412false
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Answer : 2. "8"
Explanation :
Answer: B) 8 Explanation: AmitBharatNo.of Days4540Efficiency2.22Percent(=145)2.5 Percent(=140) Amit did the work in 56 days = 56×145×2=2845 Therefore, Rest work 17/45 was done by Amit and Bharath = 174517360 = 8 days ( since Amit and Bharath do the work in one day = 145+140=17360)
Q: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 1815 05b5cc7d0e4d2b419777511d6
5b5cc7d0e4d2b419777511d6- 1200, 250, 300false
- 2300, 200, 250true
- 3200, 300, 400false
- 4None of thesefalse
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Answer : 2. "300, 200, 250"
Explanation :
Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50% B's 5 days work = 33.33% C's 2 days work = 16.66% [100- (50+33.33)] Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1 A's total share = Rs. 1500 B's total share = Rs. 1000 C's total share = Rs. 500 A's one day's earning = Rs.300 B's one day's earning = Rs.200 C's one day's earning = Rs.250
Q: Two pipes A and B can fill a tank in 24 hours and 1717 hours respectively. Harihar opened the pipes A and B to fill an empty tank and some times later he closed the taps A and B , when the tank was supposed to be full. After that it was found that the tank was emptied in 2.5 hours because an outlet pipe "C" connected to the tank was open from the beginning. If Harihar closed the pipe C instead of closing pipes A and B the remaining tank would have been filled in : 9706 05b5cc7cfe4d2b419777511cc
5b5cc7cfe4d2b419777511cc- 12 hoursfalse
- 28 hourstrue
- 36 hoursfalse
- 44 hoursfalse
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Answer : 2. "8 hours"
Explanation :
Answer: B) 8 hours Explanation: Efficiency of Inlet pipe A = 4.16% 10024 Efficiency of Inlet pipe B = 5.83% 1001717 Therefore, Efficiency of A and B together = 100 % Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x) Now, since this amount of water is being emptied by 'C' at x% per hour, then 10x10-xx=2.5 hrs => x = 8 Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours
Q: A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes? 6136 05b5cc7bbe4d2b419777509d7
5b5cc7bbe4d2b419777509d7- 14%true
- 25%false
- 36%false
- 48%false
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Answer : 1. "4%"
Explanation :
Answer: A) 4% Explanation: SP of first article = Rs.1000 Profit = 20% CP = SP x 100100+P% = Rs. 25003 SP of Second Article = Rs.1000 Loss = 20% CP = SP x 100100-L% = Rs. 1250 So, Total SP = Rs.2000; Total CP = Rs.6250/3 As the CP is more than SP, he makes a loss. Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3) So, Loss Percent = Lossx100/CP = 4%
Q: By selling an article at Rs.800, a shopkeeper makes a profit of 25%.At what price should he sell the article so as to make a loss of 25%? 3895 05b5cc7bbe4d2b419777509d2
5b5cc7bbe4d2b419777509d2- 1Rs.720false
- 2Rs.640false
- 3Rs.540false
- 4Rs.480true
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Answer : 4. "Rs.480"
Explanation :
Answer: D) Rs.480 Explanation: SP = Rs.800 ; Profit = 25% CP = SP x 100100+P% = 800 x 100100+25 = 640 Now, CP = Rs.640 Loss = 25% = 25% of Rs.640 = Rs.160 Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480
Q: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares? 3213 05b5cc7bbe4d2b419777509cd
5b5cc7bbe4d2b419777509cd- 110000 and 15000true
- 215000 and 10000false
- 35000 and 20000false
- 420000 and 5000false
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Answer : 1. "10000 and 15000"
Explanation :
Answer: A) 10000 and 15000 Explanation: As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested. Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3. Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000 Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000