GRE प्रश्न और उत्तर का अभ्यास करें

प्र: A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ? 1226 0

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    160
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  • 2
    120
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  • 3
    140
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  • 4
    180
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    गलत
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उत्तर : 4. "180"
व्याख्या :

Answer: D) 180 Explanation: Given total number of cows = kNow, 1st son share = k/22nd son share = k/43rd son share = k/54th son share = 9 (k) + (k/4) + (k/5) + 9 = k=> k - (19k/20) = 9=> (20k-19k)/20 = 9=> k = 180.

प्र: If in the following set of numbers, the first and the third digits are interchanged in each number, which number will be second from the end if arranged in ascending order after interchanging the digits ? 585  546  514  404  206  369 1116 0

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    404
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  • 2
    585
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    415
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  • 4
    602
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उत्तर : 3. "415"
व्याख्या :

Answer: C) 415 Explanation: Given numbers are 585 546 514 404 206 369Then interchanging the 1st and 3rd digits of the given numbers, we get585 645 415 404 602 963Now, arranging them in ascending order963 645 602 585 415 404Then the last second number is 415.

प्र: The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago ? 1546 0

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    2 : 5
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  • 2
    8 : 15
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  • 3
    9 : 10
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  • 4
    3 : 5
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उत्तर : 3. "9 : 10"
व्याख्या :

Answer: C) 9 : 10 Explanation: The ratio of X and Y ages at present is 4:5.  Then, the ratio 20 years ago will not be more than the ratio at present. So, from the options 9:10 is not satifying => its ratio is 0.9 which is greater than presnt ratio of 0.8.

प्र: There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ? 908 0

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    1000
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  • 2
    625
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  • 3
    525
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  • 4
    125
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उत्तर : 4. "125"
व्याख्या :

Answer: D) 125 Explanation: Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5 So total methods = 5 x 5 x 5 = 125.

प्र: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3921 0

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    10
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    18
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    12
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  • 4
    15
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उत्तर : 1. "10"
व्याख्या :

Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.

प्र: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1591 0

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    21.4 and 42.8
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  • 2
    25.2 and 50.4
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  • 3
    31.4208 and 62.8416
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  • 4
    33.12 and 66.24
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उत्तर : 3. "31.4208 and 62.8416"
व्याख्या :

Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.

प्र: There are 15 lines in plane. How many intersections (Maximum) can be made ? 1556 0

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    55
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  • 2
    105
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  • 3
    215
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  • 4
    148
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उत्तर : 2. "105"
व्याख्या :

Answer: B) 105 Explanation: First line will cut all other 14, similarly second will cut 13, and so onTotal = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.

प्र: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1197 0

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    23
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  • 2
    24
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  • 3
    25
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  • 4
    26
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उत्तर : 4. "26"
व्याख्या :

Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.

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