GRE Practice Question and Answer
8Q: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2240 05b5cc745e4d2b4197774fa0e
5b5cc745e4d2b4197774fa0e- 139 daysfalse
- 237 daysfalse
- 335 daystrue
- 433 daysfalse
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Answer : 3. "35 days"
Explanation :
Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.
Q: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1068 05b5cc745e4d2b4197774fa09
5b5cc745e4d2b4197774fa09- 11false
- 22true
- 33false
- 44false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given that x = 2+ 223 + 213 So x - 2 = 223 + 213 Now cubing on both sides, we get => x3-8-6x2+12x = 4 + 2 + 6(x-2) Therefore, x3-6x2+6x = -6 + 8 = 2
Q: A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ? 1127 05b5cc745e4d2b4197774f9fe
5b5cc745e4d2b4197774f9fe- 136 kmphtrue
- 232 kmphfalse
- 328 kmphfalse
- 434 kmphfalse
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Answer : 1. "36 kmph"
Explanation :
Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.
Q: Every year before the festive season, a brand store increases the price of the product by 42% and then introduce two successive discount of 10% and 11% respectively. What is percentage loss and percentage gain ? 1195 05b5cc745e4d2b4197774f9f9
5b5cc745e4d2b4197774f9f9- 13.25% lossfalse
- 213.742% lossfalse
- 33.25% gainfalse
- 413.742% gaintrue
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Answer : 4. "13.742% gain"
Explanation :
Answer: D) 13.742% gain Explanation: Let CP = 100,42 % increase => SP = 14210 % discount in SP => ((142 x 10)/100) = 14.2So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.0582nd SP = (127.8 - 14.058) = 113.742, So finally CP = 100, SP = 113.742, => gain = 13.742%.
Q: Choose Odd one out of the options ? 8385 05b5cc745e4d2b4197774f9f4
5b5cc745e4d2b4197774f9f4- 1PSRQfalse
- 2SVUTfalse
- 3MNPOtrue
- 4KNMLfalse
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Answer : 3. "MNPO"
Explanation :
Answer: C) MNPO Explanation: PSRQ --> {16, 19, 18, 17} - next 3 alphabets of "P" is written in reverse orderSVUT --> {19, 22, 21, 20} - next 3 alphabets of "S" is written in reverse order MNPO --> {13, 14, 16, 15} KNML --> {11, 14, 13, 12} - next 3 alphabets of "K" is written in reverse order Except "MNPO", others are not in consecutive order.
Q: In a party there are male and female members. If 15 female quit then the number of females will become double the number of males. If 45 males quit no. of female becomes five times the number of males. Find the number of females ? 1608 05b5cc741e4d2b4197774f9ef
5b5cc741e4d2b4197774f9ef- 1175true
- 2145false
- 3165false
- 4135false
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Answer : 1. "175"
Explanation :
Answer: A) 175 Explanation: Let the number of males be 'M'Let the number of females be 'F'From the given conditions,(F-15)=2M.....(i)F=5(M-45).....(ii)By solving the equations (1) & (2) we get M = 80 Then substitute M = 80 in (1)F = 2M + 15F = 2 x 80 + 15=> F = 175Therefore, number of males = 80 and females = 175 in the party.
Q: Dot cabs company provides cabs for software employees. The company has 8 Swift dzires, 6 Scorpios, 7 Innovas and few small cars. If Swift dzire makes one fourth of the total fleet, how many small cars are there in the company ? 1857 05b5cc741e4d2b4197774f9ea
5b5cc741e4d2b4197774f9ea- 19false
- 210false
- 311true
- 412false
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Answer : 3. "11"
Explanation :
Answer: C) 11 Explanation: Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.Given SD makes 1/4 th of the total fleet.=> 8 = 1/4 (21 + x)=> 32 = 21 + x=> x = 11 Therefore, the company has 11 small cars.
Q: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? 1921 05b5cc741e4d2b4197774f9e5
5b5cc741e4d2b4197774f9e5- 112 pmtrue
- 21 pmfalse
- 311 amfalse
- 411:30 amfalse
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Answer : 1. "12 pm"
Explanation :
Answer: A) 12 pm Explanation: let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon.