Answer: B) 180/11 min past 9 Explanation: At 9 o’clock, the hour hand is at 9 and the minutes hand is at 12, i.e., the two hands are 15 min. spaces apart.So, the minute hand should gain = (30 - 15) minutes = 15 minutes55 minutes will be gained in 60 min.15 minutes spaces will be gained in ((60/55) x 15) min. = 180/11 min.The hands will be in the same straight line but not together i.e.,in 180 degrees at 180/11 min. past 9.

Answer: D) 108 yrs Explanation: Let the present ages of the mother and daughter be 2x and x years respectively. Then, (2x - 18) = 3(x - 18) => x = 36 Required sum = (2x + x) = 108 years.

Answer: D) 17 Explanation: Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.P + Q = 8 ----- (1)(10Q + P) - (10P + Q) = 549(Q - P) = 54(Q - P) = 6 ----- (2)Solve (1) and (2) P = 1 and Q = 7The required number is = 17

Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.

Answer: B) 23 1/3 % Explanation: K = 100 L = 130130------ 30100------- ? => 23 1/13 %

Answer: D) 23 Explanation: As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all. Hence, no. of working days = 30 – 7 =23

Answer: D) 4 Explanation: According to the question, after the position of the first and third digit interchanged new numbers are 789, 415, 856, 784, 404, 962 962, 856, 789, 784, 404, 415Here the second lowest number is 404 and the last digit of it is '4'.

Answer: B) 225 Explanation: The series follows the following pattern 5 X 5 – 5 = 20 20 X 4 – 4 = 76 76 X 3 – 3 = 225 225 X 2 – 2 = 448 Hence, the term 225 denoted by (d) completes the series