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प्र: What is the difference in the shares of profit between P and Q in a joint business at the end of one year ? a. P Invested Rs. 80,000 and withdrew Rs. 20,000 after 6 months. b. Q joined four months after the start of business. c. Q's amount was 80% of P's amount during the last six months. 1556 0

  • 1
    Only a
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  • 2
    Only c
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  • 3
    Both a & b
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  • 4
    Data is not sufficient
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उत्तर : 4. "Data is not sufficient"
व्याख्या :

Answer: D) Data is not sufficient Explanation: a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month. b & c. Q's investment = 80% of Rs. 60000 for 8 months. = Rs.(48000 x 8) for 1 month = 384000 for 1 month P : Q = 840000 : 384000 = 35 : 16. But, the total profit is not given, so data is inadequate.

प्र: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1173 0

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    28450
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  • 2
    26340
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  • 3
    32640
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  • 4
    36450
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उत्तर : 3. "32640"
व्याख्या :

Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero.   The formula to find sum of all numbers in a permutation is   111 x no of ways numbers can be formed for a number at given position x sum of all given digits   No of 1 s depends on number of digits   So,the answer us   111 x 20 x (0+1+2+3+4+5) = 33300   We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula.   Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0.   This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number.   So the sum for this is 11 x 4 x (1+2+3+4+5). =660   Hope u understood why we use 4. Each number can be formed in 4x1 ways   So, the final answer is 33300-660 = 32640

प्र: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ? 1382 0

  • 1
    50%
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  • 2
    25%
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  • 3
    75%
    सही
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  • 4
    60%
    सही
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उत्तर : 1. "50%"
व्याख्या :

Answer: A) 50% Explanation: CP of 1000gm = Rs. 10SP of 800gm = Rs. 12SP of 1000gm =12x1000/800 = Rs. 15 Now take 1000gm as reference to calculate profit.Profit=SP-CP=15-10=Rs. 5Profit % = 5x100/10 = 50%

प्र: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ? 4112 0

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    Rs. 5500
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  • 2
    Rs. 6000
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  • 3
    Rs. 6200
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  • 4
    Rs. 6350
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उत्तर : 2. "Rs. 6000"
व्याख्या :

Answer: B) Rs. 6000 Explanation: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000

प्र: What was the day on 2nd Jan 1901 ? 3868 0

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    Tuesday
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  • 2
    Wednesday
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  • 3
    Monday
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  • 4
    Thursday
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उत्तर : 2. "Wednesday"
व्याख्या :

Answer: B) Wednesday Explanation: 2nd Jan 1901 means(1900 years and 2 day)Now, 1600 years have 0 odd day300 years have 1 odd day2 days has 2 odd dayTotal no. of odd days = 0 + 1 + 2 = 3 daysHence, the day on 2nd Jan 1901 was Wednesday.

प्र: The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ? 2820 0

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    63 and 49
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  • 2
    64 and 48
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  • 3
    62 and 46
    सही
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  • 4
    64 and 49
    सही
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उत्तर : 1. "63 and 49"
व्याख्या :

Answer: A) 63 and 49 Explanation: Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14=> x - y = 2 product of numbers = product of their hcf and lcm=> 7x * 7y = 441 * 7=> x * y = 63 Now, we havex * y = 63 , x - y = 2=> x = 9 , y = 7 The numbers are 7x and 7y=> 63 and 49

प्र: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 1611 0

  • 1
    49450
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  • 2
    50540
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  • 3
    46587
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  • 4
    52487
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उत्तर : 2. "50540"
व्याख्या :

Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed),   Total : C121×C320+C321×C120= 50540 ways.

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उत्तर : 3. "35214"
व्याख्या :

Answer: C) 35214 Explanation:

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