GATE Practice Question and Answer
8Q: Four thermal heaters A,B, C and D are used in the R & D department of Raliance chemicals Ltd. Only one heater can be used on any day . If heater A is used on any day, neither A nor C can be used the next day. If heater C is used on any day, neither C nor D can be used on the next day. If heater C is used on any day, then A has to be used the next day. If heater D is used on any day, then B has to be used the next day. If heater D is used on the third day and different heaters are used on first and fourth day, which heater is used on the first day ? (1) D (2) A (3) B (4) C 7662 05b5cc758e4d2b4197774fbcf
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Answer :
Explanation :
If heater D is used on the third day, heater B has to be used on the fourth day and A has to be used on the second day. But if A is used on second day, then either B or C has to be used on the first day. But if heater B is used on the first day, then according to the question, the requirement of having different heaters on the first day and fourth days would not be fulfilled. Hence the heater that would be used on the first day is C.
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Answer :
Explanation :
1. Answer (b) Santosh , Ujjwal and Varun must each receive at least three pieces, but Tarun must receive at least four pieces. The maximum number of pieces that any person may receive is six ( 6 + 3+ 3+3 = 15 ), and only Tarun may receive six pieces. Ujjwal and Varun each may receive as many as five pieces, while Santosh may receive only four pieces at maximum.At least one pear. 2. Answer (c) Varun may receive no more than five pieces and Tarun may receive no fewer than four pieces. As a result, if Varun receives more pieces than Tarun, then Varun must receive five pieces, and Tarun must receive four pieces. Thus, statement (a) must be true. Since Varun will receive five pieces, none of the other three friends will receive any apple, accordingly, each of the other three friends must receive at least one orange and at least one pear. Thus, statement (b) and (d) must be true.
Q: In the series given below , how many 8's are there each of which is exactly divisible by its immediate preceeding as well as succeeding numbers ?2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 2001 05b5cc758e4d2b4197774fbc4
5b5cc758e4d2b4197774fbc4- 1fivefalse
- 2fourfalse
- 3twotrue
- 4onefalse
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Answer : 3. "two"
Explanation :
Answer: C) two Explanation: Clearly, we may mark such sets of 3 numbers, in which the middle number is 8 and each of the two numbers on both sides of it is a factor of 8, as shown below : 2 8 3 8 2 4 8 2 4 8 6 8 2 8 2 4 8 3 8 2 8 6 So, there are two such 8's. Hence the answer is C.
Q: A person is asked to put in a basket one apple when ordered 'one', one guava when ordered 'two', one orange whe ordered 'three' and is asked to take out from the basket one apple and one guava both when ordered 'four'. The ordered sequence executed by the person is as follows : 1 2 3 3 2 1 4 2 3 1 4 2 2 3 3 1 4 1 1 3 2 3 4 1. How many apples will be there in the basket at the end of the above order sequence ? (a) 4 (b) 3 (c) 2 (d) 1 2. How many fruits will be there in the basket at the end of the above order sequence ? (a) 13 (b) 17 (c) 9 (d) 11 5571 05b5cc754e4d2b4197774fbc3
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Answer :
Explanation :
1. Answer (c) Each time we order 1, one apple is added to the basket but each time when 4 is ordered, one apple is removed from it. Required number of apples = number of 1's - number of 4's = 6 - 4 = 2 2. Answer (d) Each time we order 1, 2 or 3, one fruit is added to the basket but when ever we order 4, two fruits are removed from it. Required number = Number of 1's + Number of 2's + Number of 3's - 2 x (Number of 4's) = 6 + 6 + 7 - (2x4) = 19 - 8 = 11.
Q: Statement: There was a spurt in criminal activities in the city during the recent festival season.Courses of action:a. The police should immediately investigate into the causes of this increase.b. In future the police should take adequate precaution to avoid recurrence of such situation during festival.c. The known criminals should be arrested before any such season. 1359 05b5cc754e4d2b4197774fbbe
5b5cc754e4d2b4197774fbbe- 1Both a and b followstrue
- 2Only c followsfalse
- 3Only a followsfalse
- 4Both b and c followsfalse
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Answer : 1. "Both a and b follows"
Explanation :
Answer: A) Both a and b follows Explanation: The police ought to find out the lackenings in existing security arrangements and make up for these inadequacies to strengthen security and thus prevent criminal activities in the forthcoming festival. So, both a and b follow. Arresting the known criminals does not ensure safety, for a novice can also indulge in crime. So, c does not follow.
Q: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 2471 05b5cc754e4d2b4197774fbb4
5b5cc754e4d2b4197774fbb4- 1215false
- 2315true
- 3415false
- 4115false
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Answer : 2. "315"
Explanation :
Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect. Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines. Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315
Q: A polygon has 44 diagonals, then the number of its sides are ? 1085 05b5cc754e4d2b4197774fbb9
5b5cc754e4d2b4197774fbb9- 113false
- 29false
- 311true
- 47false
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Answer : 3. "11"
Explanation :
Answer: C) 11 Explanation: Let the number of sides be n. The number of diagonals is given by nC2 - n Therefore, nC2 - n = 44, n>0 nC2 - n = 44 n2 - 3n - 88 = 0 n2 -11n + 8n - 88 = 0 n(n - 11) + 8(n - 11) = 0 n = -8 or n = 11. As n>0, n will not be -8. Therefore, n=11.
Q: There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ? 3739 05b5cc754e4d2b4197774fbaf
5b5cc754e4d2b4197774fbaf- 1105true
- 27! x 6!false
- 37!/5!false
- 4420false
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Answer : 1. "105"
Explanation :
Answer: A) 105 Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room, Then, 7C1 x 6C2 x 4C4 = 7 x 15 x 1 = 105